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Converting periodic function from radians to time?

  1. Dec 2, 2012 #1
    1. The problem statement, all variables and given/known data
    Hey guys. So I have this homework exercise where I have to convert the following periodic function in radians into a periodic function in time.

    f(θ) = (80/∏2) θ, -∏/2 ≤ θ ≤ ∏/2
    (80/∏) - (80/∏2) θ, ∏/2 ≤ θ ≤ 3∏/2

    2. Relevant equations

    θ = ω0 t
    ω0 = 2∏/T

    3. The attempt at a solution

    After substituting the relevant equations into the original equation and using a bit of logic regarding the periods and time intervals, I got the following function:

    (160t)/(∏ * T) , -T/4 ≤ t ≤ T/4
    (80T -160)/(∏ * T) t, T/4 ≤ t ≤ 3T/4


    However, I don't know if this is the correct input. I would appreciate it if anyone could tell me if my calculations are correct.

    Thank you all very much.
     
  2. jcsd
  3. Dec 5, 2012 #2

    Ibix

    User Avatar
    Science Advisor

    I agree your algebra. However, your revised function isn't periodic; it's only defined on the range -T/4≤t<3T/4.

    How can you modify the range to reflect the periodicity?
     
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