Converting periodic function from radians to time?

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SUMMARY

The discussion focuses on converting a periodic function defined in radians into a time-based periodic function. The original function, f(θ) = (80/∏2) θ for -∏/2 ≤ θ ≤ ∏/2 and f(θ) = (80/∏) - (80/∏2) θ for ∏/2 ≤ θ ≤ 3∏/2, is transformed using the relationships θ = ω0 t and ω0 = 2∏/T. The resulting function is (160t)/(∏ * T) for -T/4 ≤ t ≤ T/4 and (80T - 160)/(∏ * T) t for T/4 ≤ t ≤ 3T/4. However, the revised function is noted to lack periodicity, prompting a need for adjustments to the time range to ensure periodic behavior.

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jean28
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Homework Statement


Hey guys. So I have this homework exercise where I have to convert the following periodic function in radians into a periodic function in time.

f(θ) = (80/∏2) θ, -∏/2 ≤ θ ≤ ∏/2
(80/∏) - (80/∏2) θ, ∏/2 ≤ θ ≤ 3∏/2

Homework Equations



θ = ω0 t
ω0 = 2∏/T

The Attempt at a Solution



After substituting the relevant equations into the original equation and using a bit of logic regarding the periods and time intervals, I got the following function:

(160t)/(∏ * T) , -T/4 ≤ t ≤ T/4
(80T -160)/(∏ * T) t, T/4 ≤ t ≤ 3T/4


However, I don't know if this is the correct input. I would appreciate it if anyone could tell me if my calculations are correct.

Thank you all very much.
 
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I agree your algebra. However, your revised function isn't periodic; it's only defined on the range -T/4≤t<3T/4.

How can you modify the range to reflect the periodicity?
 

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