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Converting periodic function from radians to time?

  • Thread starter jean28
  • Start date
  • #1
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Homework Statement


Hey guys. So I have this homework exercise where I have to convert the following periodic function in radians into a periodic function in time.

f(θ) = (80/∏2) θ, -∏/2 ≤ θ ≤ ∏/2
(80/∏) - (80/∏2) θ, ∏/2 ≤ θ ≤ 3∏/2

Homework Equations



θ = ω0 t
ω0 = 2∏/T

The Attempt at a Solution



After substituting the relevant equations into the original equation and using a bit of logic regarding the periods and time intervals, I got the following function:

(160t)/(∏ * T) , -T/4 ≤ t ≤ T/4
(80T -160)/(∏ * T) t, T/4 ≤ t ≤ 3T/4


However, I don't know if this is the correct input. I would appreciate it if anyone could tell me if my calculations are correct.

Thank you all very much.
 

Answers and Replies

  • #2
Ibix
Science Advisor
Insights Author
6,444
5,141
I agree your algebra. However, your revised function isn't periodic; it's only defined on the range -T/4≤t<3T/4.

How can you modify the range to reflect the periodicity?
 

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