- #1

atrus_ovis

- 101

- 0

( '*' is the convolution operator)

its FT X(Ω)=(1/2π) F(sin(πt)) * F(sin(50πt))

= (1/2π) jπ(δ(Ω+π)-δ(Ω-π)) * (jπ (δ(Ω+π)-δ(Ω-π)) ) (a)

from my professor's solution it next goes:

= (π/2) (-δ(Ω+π)+δ(Ω-π)) * ((-δ(Ω+π)+δ(Ω-π)) ) (b)

1)How did the signs change?

2)Where did the j's go? ( i suspect 1,2 are related =P )

also,

3) doesn't the 1/π cancel out the π coefficients in each quantity to be convoluted?

from wiki:

a (f * g) = (a f) * g = f * (a g)

why is that? i mean, why isn't it:

a (f * g) = (a f) *(a g)

?