(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

How does ∂_{a}A^{b}behave under coordinate transformations in special relativity? Work out ∂'_{a}A'^{b}

2. Relevant equations

3. The attempt at a solution

I have been given back the solution sheet to this problem, but I don't understand it. This is what I have

I get the first line, (13). We have treated the partial as a covariant vector, and written out the usual transform for it. The part within the brackets is the normal transform of a contravariant vector A.

Looking at (14), the text says we have used the product rule here. I am familiar with this in normal calculus, where if k(x) = f(x)g(x) then k'(x) = f'(x)g(x) + f(x)g'(x). If I apply that here, I would expect to see ∂'_{a}A^{b}+ ∂_{a}A'^{b}

Written out long hand, this would be similar to (14). However, the solution has an extra ∂X^{d}/∂X'^{a}in the second term, and that weird ∂∂X'^{b}thing in the first term.

For the second term in (14) we have every item in (13) just multiplied together in a different order; and the first term in (14) is the same, but with two of those items conflated to form the ∂∂X'^{b}strangeness. Are they multiplied together in some sense, or is this now a second order partial derivative term? What on earth is going on? If someone could post up a clear rule for how to approach this type of problem it would be great, as it will keep cropping up in my course and I am totally clueless how else to tackle it.

My tutor advised me to take a look at the wikipedia link for the chain rule, but I can't see how that is relevant to this problem, although I see it is different in higher dimensions to what I am used to. I have also searched to see if the product rule is different in higher dimensions, but it seems to work just the same for vectors as for normal functions.

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# Homework Help: Coordinate transform of partial derivative

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