Coordinate transformation - NED and ECEF frames

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To transform accelerations from the sensor's body frame to the Earth Centered Earth Fixed (ECEF) frame, the rotation matrix R(North East Down to ECEF) can be derived using latitude and longitude. The formula provided for R(NED to ECEF) utilizes trigonometric functions of latitude and longitude, which are crucial for accurate conversion. It is important to note that while this matrix is typically used for coordinates, its applicability to vector transformations may require further validation. The overall transformation from the body frame to ECEF can be expressed as Acceleration(ECEF) = R(Body to ECEF) * Acceleration(Body frame). Ensuring the correct application of these transformations is essential for accurate acceleration data representation in the ECEF frame.
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Hi,

I have a reference device that outputs euler angles, which are angles that relate the sensor body frame to the north east down frame. These angles are called pitch roll and yaw. The sensor is an accelerometer. I know how to get the rotation matrix that will put accelerations from the accelerometer sensor body frame to the north east down frame. Call this rotation matrix R(Body to North East Down).

How do I get the rotation matrix that will rotate from Body frame to Earth Centered Earth Fixed frame? I need to do this as all of my other calculations use the Earth Centered Earth Fixed frame. I can see that:

R(Body to Earth Centred Earth Fixed) = R(Body to North East Down) * R(North East Down frame to Earth Centered Earth Fixed).

How do I get R(North East Down frame to Earth Centered Earth Fixed)?

To get acceleration in the Earth centered Earth fixed frame, would I use:
Acceleration(Earth Centred Earth Fixed) = R(Body to Earth Centred Earth Fixed)*Acceleration(Body frame) ?

I have access to the position in latitude and longitude (radians). Also note that acceleration is a vector not a coordinate.

Thanks.
 
Latitude and longitude give you the rotation angles to convert from NED to ECEF. I am working from vague memory, but I think that the latitude gives the rotation angle needed even when you are using the accurate WGS84 Earth model. If you have magnetic north, don't forget to rotate to true north.
 
R(North East Down frame to Earth Centered Earth Fixed) =

[ sinLatitude*cosLongitude; -sinLongitude; -cosLatitude*cosLongitude]
[-sinLatitude*sinLongitude; cosLongitude; -cosLatitude*sinLongitude]
[cosLatitude; 0; -sinLatitude; ]

I am unsure if this is correct for my application because this may only be relevant for coordinates not vectors. Please comment.
 
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