Coordinates and change of base

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robertjford80
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Homework Statement


Textbook page under the heading Coordinates: two bases for R^2, standard basis S and basis B = {v1, v2} with v1 = [1 2] and v2 = [3 1], and Example 1 with x = [11 7] and y = [-5 5], giving x = 11e1 + 7e2 = 2v1 + 3v2 and y = -5e1 + 5e2 = 4v1 - 3v2.




The Attempt at a Solution



I don't understand where 2v1 + 3v2
and
4v1 - 3v2

came from.
 
I see that the vectors are raised to T which I'm pretty sure means they're transposed but that still doesn't get me anywhere.
 
Where's Figure 3.29a? You should post the whole example to help us get a clearer picture of the problem.
 
You are solving the equations
[tex]x= \begin{bmatrix}11 \\ 7\end{bmatrix}= a\begin{bmatrix}1 \\ 2\end{bmatrix}+ b\begin{bmatrix}3 \\ 1\end{bmatrix}[/tex]
which is the same as the two equations a+ 3b= 11 and 2a+ b= 7. Can you solve for a and b?
And
[tex]y= \begin{bmatrix}-5 \\ 5\end{bmatrix}= c\begin{bmatrix}1 \\ 2\end{bmatrix}+ d\begin{bmatrix}3 \\ 1\end{bmatrix}[/tex]
which is the same as the two equations c+ 3d= -5 and 2c+ d= 5. Can you solve for a and b?
 
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