Coriolis and different refererence frames

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    Coriolis Frames
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SUMMARY

The discussion focuses on understanding the Coriolis effect, particularly how it influences the eastward and westward deflection of objects in different reference frames. When an object is dropped from a height, it experiences eastward deflection due to its initial tangential velocity, which is greater than that of the ground. For a ball thrown straight up, the westward deflection is calculated once for both the ascent and descent phases, as the westward acceleration during ascent cancels with the eastward acceleration during descent, resulting in a net westward landing position. The Java applet provided by the user serves as a practical tool for visualizing these effects.

PREREQUISITES
  • Understanding of the Coriolis effect
  • Familiarity with inertial and rotating reference frames
  • Basic principles of angular momentum conservation
  • Knowledge of projectile motion
NEXT STEPS
  • Explore the Java applet at this link for practical visualization of projectile motion.
  • Study the textbook 'Classical Dynamics' by Stephen Thornton and Jerry Marion for in-depth discussions on dynamics and Coriolis effects.
  • Research Kepler's laws of orbital motion to understand the relationship between speed and gravitational pull.
  • Learn about the mathematical derivation of the Coriolis force in various contexts.
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Physics students, educators, and anyone interested in the dynamics of motion under the influence of the Coriolis effect and related forces.

Wondering
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Hello,

I am stuck on the coriolis force. If an object is dropped how do I get the eastward deflection when looking from an inertial frame? I know how from the rotating frame but for some reason I am stuck, i.e. what terms to use.
Also, if I throw a ball straight up from Earth what is the westward deflection, do I solve this twice? Once for the ball moving up and then again once it is at the max height falling down?

Thank you
 
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Wondering said:
Hello,
I am stuck on the coriolis force. If an object is dropped how do I get the eastward deflection when looking from an inertial frame?
What you see there initially is the ball that has the same angular velocity but a higher tangential velocity than the ground. As it descends it outruns the ground due to that higher tangential velocity. The angular velocity of the ball increases to preserve it's angular momentum.
Wondering said:
Also, if I throw a ball straight up from Earth what is the westward deflection, do I solve this twice? Once for the ball moving up and then again once it is at the max height falling down?
Yes the west acceleration during rise is canceled by the east acceleration during fall, so the ball lands with zero velocity in the east-west direction, but in a point west to the throw position. The defection is the same during both phases, so you just calculate it once and multiply by two.
 
Last edited:
Wondering said:
Hello,
I am stuck on the coriolis force. If an object is dropped how do I get the eastward deflection when looking from an inertial frame? I know how from the rotating frame but for some reason I am stuck, i.e. what terms to use.
Also, if I throw a ball straight up from Earth what is the westward deflection, do I solve this twice? Once for the ball moving up and then again once it is at the max height falling down?
Thank you

I won't give you the derivations, but you can check your results against the following Java applet that is available on my website. http://www.cleonis.nl/physics/ejs/ballistics_and_orbits_simulation.php"
The Coriolis effect is the main subject of my website. (http://www.cleonis.nl)

The applet http://www.cleonis.nl/physics/ejs/ballistics_and_orbits_simulation.php" shows the motion of a launched object. The panel on the left shows the motion with respect to the inertial coordinate system, the panel on the right shows the motion with respect to the coordinate system that is co-rotating with the Earth.

You can launch from any latitude, you can launch at any angle (eastward, westward etc), you can launch at any elevation, and you can specify the nozzle velocity (zero for release to free motion, high speed for launch with a gun.)

If memory serves me the textbook 'Classical dynamics' by (authors Stephen Thornton and Jerry Marion) offers several discussions.

If an object is dropped from a high tower, why does it not land at the base of the tower? Answer: (simplified version that neglects air resistance effects). Once the object is released it is effectively in orbital motion. (An orbit that will be shortlived, as it intersects the Earth's surface.)
There is Kepler's law for orbital motion: when an orbiting object is pulled closer to its primary its speed increases, (in such a way that equal areas are swept out in equal intervals of time.)
An extreme example is the orbit of Halley's comet: during the part of the orbit that the comet is falling to the center of the solar system the comet is gaining speed all the time. Halley's comet sweeps around the Sun, and then starts climbing outward again. Moving against the pull of the Sun the comet is losing velocity all the time.

Returning to the example of releasing an object from the top of a high tower: the Earth's gravity is pulling the object in, so the angular velocity of the object increases. The Java applet I mentioned is also designed to illustrate the 'object released from high tower' scenario.

In this particular case the fastest calculation strategy to obtain the motion with respect to the inertial coordinate system is to apply conservation of angular momentum.

Cleonis
http://www.cleonis.nl
 
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