Cosmological Expansion: Estimating Present Horizon Length

Kyrios
Messages
28
Reaction score
0

Homework Statement


If light traveled a distance L = H_{eq}^{-1} at M-R equality, how large does this distance expand to at present? (in Mpc)

Homework Equations


z_{eq} = 3500
\Omega_m = 0.32 at present
\rho_c = 3.64 \times 10^{-47} GeV^4 present critical density

The Attempt at a Solution


Not entirely certain where to begin for this one. I think it's asking for the horizon length at present, so perhaps need to use the equation
L =a(t) \int \frac{da}{a^2 H}
 
Physics news on Phys.org
Since the problem quotes ##L = H_{\rm eq}^{-1}##, I suspect that what they want you to do is to compute (roughly) the present size of a region that was in causal contact at the time of matter-radiation equilibrium.
 
So would this be done by calculating H_{eq} at equality, and then expanding with scale factor, L(z=0) = L_{eq} (1 + z_{eq}) ?
If I do that, it gives a value a little under 150 Mpc.
 
This is the approach I would take - assuming that my interpretation of the problem is correct.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top