Well, if all your movements were sped up by a factor of N, then your initial upwards velocity when jumping should increase by a factor of N as well, so you'd go a lot higher...in general, if you jump upwards with initial velocity v_0, your initial kinetic energy is (1/2)mv_0^2, and your potential energy as you go upwards is given by mhg, with mhg = (1/2)mv_0^2 at maximum height, giving a height of h = (1/2g)v_0^2. So, if you increase v_0 by N then h will increase by N^2, meaning height you are able to jump also increases by the square of the speedup factor. And note that this equations says that if you went to a planet where the gravitational acceleration g was decreased by a factor of N^2, this would also increase the height you could jump by a factor of N^2.
Likewise, if you increase your rate of perception by a factor of N it obviously takes a falling object N times as long to fall the same distance...so we might ask, is it also true that if you go to a planet where the gravitational acceleration is decreased by a factor of N^2, while your rate of perception remains unchanged, then on this planet it takes a falling object N times as long to fall a given distance? Well, if an object is falling with acceleration g from a state of rest, its velocity as a function of time is v(t) = gt and its position (measured downward from its starting points) as a function of time is x(t) = (g/2)*t^2, so if you decrease g by factor of N^2, you must indeed increase t by a factor of N in order for the object to fall the same distance x. So, it seems like an observer whose perceptions are sped up by a factor of N will see gravitational phenomena work exactly the same way as if he had not been sped up but if gravity had decreased by a factor of N^2 (this is ignoring changes unrelated to gravity, like the apparent decrease in inertial mass of objects around the sped-up observer that I discussed earlier).