Identical isolated conducting spheres 1 and 2 have equal charges and are separated by a distance that is large compared with their diameters. The magnitude of the electrostatic force acting on sphere 2 due to sphere 1 is F = 8.9 N. Suppose now that a third identical sphere 3, having an insulating handle and initially neutral, is touched first to sphere 1, then to sphere 2, and finally removed. What is the magnitude of the electrostatic force F' that now acts on sphere 2?(adsbygoogle = window.adsbygoogle || []).push({});

so when sphere 3 touches sphere one, the charge is transfered by 1/2. so the force is then 4.45.

when sphere 3 then touches sphere 2 i thought u added the charges? so 4.45N + 8.9N? which is 13.35N?

i think im missing something...

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# Homework Help: Coulombs Law and electrostatic force

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