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Definition/Summary
Coulomb's law is an inverse-square law stating that the force vector between two stationary charges is a constant times the unit vector between them and times the product of the magnitudes of the charges divided by the square of the distance between them: \mathbf{F}_{12}\ \propto\ Q_1Q_2\,\mathbf{\hat{r}}_{12}/r_{12}^2
That constant (Coulomb's constant) is the same in any material, and is 1/4\,\pi\,\varepsilon_0, where \varepsilon_0 is the electric constant (the permittivity of the vacuum, with dimensions of charge²/force.area, and measured in units of farads/metre), and 4\,\pi is the ratio between the surface area of a sphere and the radius squared.
If the charges have the same sign, then Q_1Q_2 is positive, and the force vector points outward (the force is repulsive); if they have opposite signs, then Q_1Q_2 is negative, and the force vector points inward (the force is attractive).
Gauss' law (one of Maxwell's equations) may be derived from Coulomb's law.
Equations
Force on stationary charge 2 from stationary charge 1:
\mathbf{F}_{12}\ =\ \frac{Q_1\,Q_2}{4\,\pi\,\varepsilon_0\,r_{12}^2}\,\mathbf{\hat{r}}_{12}
Electric field of charge 1 at position of charge 2 (from Lorentz force equation):
\mathbf{E}_{12}\ =\ \frac{\mathbf{F}_{12}}{Q_2}\ =\ \frac{Q_1}{4\,\pi\,\varepsilon_0\,r_{12}^2}\,\mathbf{\hat{r}}_{12}
Since this is independent of the magnitude of charge 2, it may be rewritten:
\mathbf{E}_1(\mathbf{r})\ =\ \frac{Q_1}{4\,\pi\,\varepsilon_0\,r^2}\,\mathbf{\hat{r}}\ =\ \frac{Q_1}{\varepsilon_0\,A(r)}\,\mathbf{\hat{r}}
where A(r) is the surface area of the sphere S(r) through \mathbf{r} with charge 1 at its centre.
Obviously, the divergence of \mathbf{E}_1 at any point other than the position of charge 1 is zero (differential form of Gauss' law for zero charge density \rho):
\nabla\cdot\mathbf{E}_1\ =\ 0\ \ \text{if}\ \ \rho\ =\ 0
And the flux of \mathbf{E}_1 through the sphere S(r) is Q_1/\varepsilon_0:
\oint_{S(r)}\,\mathbf{E}_1\cdot(\mathbf{\hat{r}}\,dA)\ =\ \frac{Q_1}{\varepsilon_0 \,A(r)}\,\oint_{S(r)}\,\mathbf{\hat{r}}\cdot\mathbf{\hat{r}}\,dA\ =\ \frac{Q_1}{\varepsilon_0 \,A(r)}\,\oint_{S(r)}dA\ =\ \frac{Q_1}{\varepsilon_0}
and so, from Stoke's theorem, the flux of \mathbf{E}_1 through any closed surface S containing charge 1 is Q_1/\varepsilon_0 and through any other closed surface is zero:
\oint_S \, \mathbf{E}_1 \cdot(\mathbf{\hat{n}} \, dA)\ =\ \left\{\begin{array}{cc}<br /> Q_1/\varepsilon_0 & \text{if S contains charge 1}\\<br /> 0 & \text{if S does not contain charge 1}\end{array}\right.
Extended explanation
* This entry is from our old Library feature. If you know who wrote it, please let us know so we can attribute a writer. Thanks!
Coulomb's law is an inverse-square law stating that the force vector between two stationary charges is a constant times the unit vector between them and times the product of the magnitudes of the charges divided by the square of the distance between them: \mathbf{F}_{12}\ \propto\ Q_1Q_2\,\mathbf{\hat{r}}_{12}/r_{12}^2
That constant (Coulomb's constant) is the same in any material, and is 1/4\,\pi\,\varepsilon_0, where \varepsilon_0 is the electric constant (the permittivity of the vacuum, with dimensions of charge²/force.area, and measured in units of farads/metre), and 4\,\pi is the ratio between the surface area of a sphere and the radius squared.
If the charges have the same sign, then Q_1Q_2 is positive, and the force vector points outward (the force is repulsive); if they have opposite signs, then Q_1Q_2 is negative, and the force vector points inward (the force is attractive).
Gauss' law (one of Maxwell's equations) may be derived from Coulomb's law.
Equations
Force on stationary charge 2 from stationary charge 1:
\mathbf{F}_{12}\ =\ \frac{Q_1\,Q_2}{4\,\pi\,\varepsilon_0\,r_{12}^2}\,\mathbf{\hat{r}}_{12}
Electric field of charge 1 at position of charge 2 (from Lorentz force equation):
\mathbf{E}_{12}\ =\ \frac{\mathbf{F}_{12}}{Q_2}\ =\ \frac{Q_1}{4\,\pi\,\varepsilon_0\,r_{12}^2}\,\mathbf{\hat{r}}_{12}
Since this is independent of the magnitude of charge 2, it may be rewritten:
\mathbf{E}_1(\mathbf{r})\ =\ \frac{Q_1}{4\,\pi\,\varepsilon_0\,r^2}\,\mathbf{\hat{r}}\ =\ \frac{Q_1}{\varepsilon_0\,A(r)}\,\mathbf{\hat{r}}
where A(r) is the surface area of the sphere S(r) through \mathbf{r} with charge 1 at its centre.
Obviously, the divergence of \mathbf{E}_1 at any point other than the position of charge 1 is zero (differential form of Gauss' law for zero charge density \rho):
\nabla\cdot\mathbf{E}_1\ =\ 0\ \ \text{if}\ \ \rho\ =\ 0
And the flux of \mathbf{E}_1 through the sphere S(r) is Q_1/\varepsilon_0:
\oint_{S(r)}\,\mathbf{E}_1\cdot(\mathbf{\hat{r}}\,dA)\ =\ \frac{Q_1}{\varepsilon_0 \,A(r)}\,\oint_{S(r)}\,\mathbf{\hat{r}}\cdot\mathbf{\hat{r}}\,dA\ =\ \frac{Q_1}{\varepsilon_0 \,A(r)}\,\oint_{S(r)}dA\ =\ \frac{Q_1}{\varepsilon_0}
and so, from Stoke's theorem, the flux of \mathbf{E}_1 through any closed surface S containing charge 1 is Q_1/\varepsilon_0 and through any other closed surface is zero:
\oint_S \, \mathbf{E}_1 \cdot(\mathbf{\hat{n}} \, dA)\ =\ \left\{\begin{array}{cc}<br /> Q_1/\varepsilon_0 & \text{if S contains charge 1}\\<br /> 0 & \text{if S does not contain charge 1}\end{array}\right.
Extended explanation
* This entry is from our old Library feature. If you know who wrote it, please let us know so we can attribute a writer. Thanks!