MHB Coulomb's Law: Find Force of 4.0 & 6.0 $\mu C$ Charges

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    Coulomb's law Law
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Coulomb's Law is applied to calculate the forces between two point charges, with one charge (q1 = 4.0 μC) at the origin and another charge (q2 = 6.0 μC) located 3.0 m away on the x-axis. The force on charge q2 can be determined using the formula F = k * (q1 * q2) / r², where k is Coulomb's constant. The force on q1 is equal in magnitude and opposite in direction to the force on q2 due to Newton's third law. If q2 were to be negative (-6.0 μC), the direction of the forces would change, indicating an attractive force between the charges. Understanding these principles is crucial for mastering concepts in introductory physics.
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$\tiny{18.3.6 Coulomb's Law }$
$\text{A charge of $q_1=4.0 \mu \, C$ is at origin, and charge}$
$\text{$q_2=6.0 \mu \, C$ is on the x-axis at $x=3.0 m$ }$,
$\text{(a) find the force on the charge $q_2$ } $
$\text{(b) find the force on $q_1$ } $
$\text{(c) how would your answer for parts (a) and (b) dffer if $q_2=-6.0 \mu \, C $ }$

ok I plan to take physics 151this fall
so trying to do some expected problems early
 
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karush said:
$\tiny{18.3.6 Coulomb's Law }$
$\text{A charge of $q_1=4.0 \mu \, C$ is at origin, and charge}$
$\text{$q_2=6.0 \mu \, C$ is on the x-axis at $x=3.0 m$ }$,
$\text{(a) find the force on the charge $q_2$ } $
$\text{(b) find the force on $q_1$ } $
$\text{(c) how would your answer for parts (a) and (b) dffer if $q_2=-6.0 \mu \, C $ }$

ok I plan to take physics 151this fall
so trying to do some expected problems early
Start with Coulomb's law!

[math]F = \dfrac{k q_1 q_2}{r^2}[/math] or [math]F = \dfrac{1}{4 \pi \epsilon _0} \dfrac{q_1 q_2}{r^2}[/math]

(Hint: The force on q1 is the same as the force on q2. Why?)

-Dan
 
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