Net Force of A: Diagram Analysis

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To find the net force on object A, the relevant equations include the force between charges FAB=KqAqB/r², and the components of the forces Fx=Fcosθ and Fy=Fsinθ. The total force can be calculated using the formula FR=sqrt(Fx² + Fy²) and determining the angle θ with θ=tan⁻¹(Fy/Fx). Participants are encouraged to calculate the vector forces F_AB and F_AC, then sum these vectors to obtain the total force acting on A. Providing the calculations will help clarify the process.
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Homework Statement
Find the net force of A as shown in the diagram.
Relevant Equations
FAB=KqAqB/r2
Fx=Fcosθ
Fy=Fsinθ
FR=square root of the total of Fx^2+the total of Fy^2
θ=tan-1(Fy/Fx)
Find the net force of A as shown in the diagram.
 

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Well, what is your question?

## \ ##
 
I think you want to find Fnet A ...

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1646687015945.png

1646687513387.png

Tell me which part you need explanation.
 
Spotify said:
Homework Statement:: Find the net force of A as shown in the diagram.
Relevant Equations:: FAB=KqAqB/r2
Fx=Fcosθ
Fy=Fsinθ
FR=square root of the total of Fx^2+the total of Fy^2
θ=tan-1(Fy/Fx)

Find the net force of A as shown in the diagram.
You need to find the vector forces ## F_{AB} ## and ## F_{AC} ## and sum those force vectors to get the total force on A. Can you show us your work on that?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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