Counting 1-D Subspaces of Z_3^3

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    Counting Subspaces
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Homework Help Overview

The discussion revolves around counting the number of 1-dimensional subspaces in the vector space Z_3^3. Participants are examining the properties of vectors in this space and their spans, particularly focusing on the implications of non-zero vectors and their multiples.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • One participant attempts to calculate the number of 1-dimensional subspaces based on the total number of vectors and their spans, while another questions the validity of this approach. There is a reference to a similar calculation in Z_3^2, prompting a comparison and exploration of why the reasoning might differ in Z_3^3.

Discussion Status

Participants are actively engaging with the problem, with some providing hints and others expressing confusion about certain concepts, such as drawing the space as a lattice. There is an acknowledgment of differing interpretations regarding the counting of subspaces.

Contextual Notes

One participant mentions a lack of understanding regarding the lattice representation and its relevance to the problem, indicating a potential gap in foundational knowledge that may affect the discussion.

latentcorpse
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how many 1 dimensional subspaces of Z_3^3 are there?

Z_3^3 has 3^3 = 27 vectors

26 of which are non zero

then we can say v and 2v have the same span and so there are in fact 13 1 dimensional subspaces. is this true?
 
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No that doesn't make sense.

Hint: Draw the space as a lattice.
 
for Z_3^2, my lecturer does the following:

there are 3^2=9 elements
8 are non zero
v and 2v have the same span
therefore there are 4 1 dimensional subspaces

why can't this be extended to Z_3^3

i don't know how to draw it as a lattice or what that means to be honest...
 
Ok that does make sense, sorry. Here's why he argument works: The non-zero elements of the group Z3 all have order three, so that means that if v is a non zero element of Z3xZ3, v and 2v will be distinct, and 3v will be (0, 0, 0), so {v, 2v, 3v} will be a one dimensional subgroup generated by v.
 

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