Counting Game - A Fun Forum Word Game

[Mattara]

Counting Game

This forum word game is simple. You start of with "1" and the next person posts the number following it (2), the next posts the number following it (3) and so on.

No double posting
If an incorrect number is posted, then carry on with the correct number.

I'll start:

1

Note: I sent a pm to Evo and she told me that this doesn't qualify as spam

 

[Rach3]

\sqrt{4}The message I have entered is too short! Please lengthen it to ten characters.

 

[mattmns]

pff I got beat

\left\lfloor \pi \right\rfloor

 

[Cyrus]

Thread Locked.

 

[Rach3]

mattmns messed up (already?), so I'll continue:

edit: mattmns edited his post, so now I'll have to edit mine, dang it!

3+1

 

[mattmns]

e^{i\pi} +3!

 

[Rach3]

2^2\cdot\frac{2+2^{2-2}}{2}

 

[Mattara]

no, no NO!

Next correct number in line is:

2

 

[heartless]

3 (is this right?)

 

[mattmns]

no, no NO!

Next correct number in line is:

2

This is physicsforums, we must have fun!

Now I believe Rach just finished 6.

\frac{\partial}{\partial x} 7xy^2

 

[Mattara]

3 (is this right?)

4

lengening message to minimum of 10 char[/size]

 

[Rach3]

This is physicsforums, we must have fun!

Now I believe Rach just finished 6.

\frac{\partial}{\partial x} 7xy^2

No, no, that doesn't work! Try:

\left\lfloor \mbox{ 2nd zero of } J_1(x) \right\rfloor

 

[mattmns]

2

Mattara you double posted! You posted 1 and then you posted 2, that, in my opinion, is breaking the rules! The rules which you stated!

 

[mattmns]

No, no, that doesn't work! Try:

\left\lfloor \mbox{ 2nd zero of } J_1(x) \right\rfloor

Aww crap, you are right! What I wrote is 7y^2 lol.

 

[Rach3]

Actually the next person needs to post "eight", I can't do it because I posted "seven"...

 

[mattmns]

Alright I will do 8, that is, if I don't screw it up.

\underbrace{1 + 1 + ... + 1}
...[/color]8

 

[Rach3]

Hurray! Moving on:

\left(e^{3}\right)^{\ln 3}

 

[Cyrus]

Infinity, game over.

 

[Rach3]

Infinity, game over.

You skipped some.

 

[mattmns]

\sum_{n=1}^4 n

 

[Rach3]

Recapping, here's what he have so far:

mattara: 1
Rach3: \sqrt{4}
mattmns: \left\lfloor \pi \right\rfloor
Rach3: 3+1
mattmns: e^{i\pi} +3!
Rach3: 2^2\cdot\frac{2+2^{2-2}}{2}
Rach3 correcting mattmns: \left\lfloor \mbox{ 2nd zero of } J_1(x) \right\rfloor
mattmns: \underbrace{1 + 1 + ... + 1}
Rach3: \left(e^{3}\right)^{\ln 3}
mattmns: \sum_{n=1}^4 n

 

[Rach3]

Number of neutrons in sodium-22.

 

[mattmns]

One Dozen.

 

[Rach3]

One fortnight per day.

edit: The previous poster deleted his "13".

So now I'll have to edit:

One fortnight per day minus 1 kilogram per million milligrams

 

[heartless]

\noindent\(\pmb{\frac{\prod _{n=1}^4 n}{2} + 1}\)

 

[scott1]

( \infty - \infty ) + 150 - 137

 

[Rach3]

heartless - I already did 13, we're on 14 now.
scott1 - that's undefined.

 

[ranger]

George H. W. Bush becomes ill on a visit in Japan and vomits on the Japanese Prime Minister

-1992

 

[scott1]

George H. W. Bush becomes ill on a visit in Japan and vomits on the Japanese Prime Minister

-1992

The amount of people making fun of him for all history.

 

[Mk]

scott1 - that's undefined.

Not if you define it as 14.

15.

 

[JasonRox]

The posts are already being counted.

 

[scott1]

one minutes ago

 

[mattmns]

one minutes ago

huh?


fünfzehn

 

[scott1]

huh?

18:18-18:17 =1

 

[mattmns]

OK, but you were supposed to do number 15.

 

[Rach3]

Can't you people count?

 

[scott1]

Can't you people count?

The estimated amount of PFers that can't count.

 

[Mattara]

The correct number in line is:

5

 

[VietDao29]

The correct number in line is:

5

Nah, nah, it's 16.
5 = e ^ {i \pi} + 3!, as already proposed by mattmns.
-------------
16 = \sum_{n = 1} ^ 5 (n) - e ^ {i \pi}

 

[Mattara]

6

Come on guys, stick to the rules -_-

 

[scott1]

7 more days of the month

 

[scott1]

6

Come on guys, stick to the rules -_-

Wait is this game only
1
2
3
4
5
6
7
8
9
10
etc.
Then the rules should chaged this theard would no fun if it was like that.

 

[heartless]

I vote for new rules!
New game:
One may start with any number he/she wants, the next person is to add another number making some kind of geometric/arithmetic/sequential pattern, person who adds a number that doesn't belong to the pattern, loses and is disallowed to participate until the next game. I think it would be more fun.
What do you think?

 

[Mattara]

The next number is:

8

heartless: start your own thread. Thank you.

 

[scott1]

I vote for new rules!
New game:
One may start with any number he/she wants, the next person is to add another number making some kind of geometric/arithmetic/sequential pattern, person who adds a number that doesn't belong to the pattern, loses and is disallowed to participate until the next game. I think it would be more fun.
What do you think?

I agree just counting natuarl numbers is boring.
:zzz:

10001

 

[Greg825]

Hurray! Moving on:

\left(e^{3}\right)^{\ln 3}

=27 does it not?

quick, change it to e^2!

------------------------------

xth prime where x is the nth prime where n is the first prime raised to the first prime.

 

[Mattara]

9

Hint: The next number is 10 in a non-mathematical non-equation

 

[mattmns]

Yep Rach was wrong, and he was complaining about us? I think it is too late to switch it back! I guess we have to go back to 9, our 9 that is, not Mattara's 9.

(e^2)^{ln3}

To be lazy

 

[VietDao29]

9

Hint: The next number is 10 in a non-mathematical non-equation

Nah, just counting in natural numbers is boring... Let's continue:
\prod_{i = 1} ^ 3 (i) - 4 e ^ {i \pi} = 10

 

[Chi Meson]

so is 11 next?

In base 3, it's:

102.