The problem involves determining the number of different 13-card hands that can be formed containing at least 12 hearts. Participants are exploring the combinatorial aspects of this counting question.
Some participants have offered guidance on how to approach the problem by splitting it into cases. There is an ongoing exploration of the correct counting methods, with some clarity emerging around the number of choices for hearts and non-hearts.
Participants express uncertainty about the counting process and the implications of choosing from the remaining cards. There is acknowledgment of potential language barriers affecting communication.
lionely said:Homework Statement
How many different hands of 13 cards can be obtained containing at least 12 hearts?
Homework Equations
The Attempt at a Solution
I'm confused, well I know there could be a possibility of getting 13 hearts, but I am getting confused trying to work out the other possibilities.
lionely said:Well, because wouldn't each of the 40 cards left to be chosen from be a choice? I'm not sure how to express it
lionely said:Sorry aren't there 39 choices for the nonheart? and the number of ways of picking 39 nonhearts would it just be 39 ways?
lionely said:Sorry , for my poor English. Well to pick 12 hearts out of 13... that would be 13C12 so... 13 ways.
So the total amount of ways would be (13 x 39) + that one way of picking all 13 hearts?