What is the formula for calculating force in a crank and slider mechanism?

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SUMMARY

The formula for calculating force in a crank and slider mechanism is influenced by the angle between the plates and their respective weights. In this discussion, the plates weigh 1kg each and are 0.5m in length. The force required to push plate B varies non-linearly with the angle, being zero at 180 degrees and easiest at 0 degrees. Understanding trigonometric functions is essential for accurately determining the force needed at various angles.

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  • Basic understanding of trigonometric functions
  • Knowledge of mechanics, specifically crank and slider mechanisms
  • Familiarity with force calculations in physics
  • Experience with non-linear relationships in mechanical systems
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  • Study the principles of crank and slider mechanisms in mechanical engineering
  • Learn how to apply trigonometric functions to force calculations
  • Research non-linear force relationships in mechanical systems
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Mechanical engineers, physics students, and hobbyists involved in designing and analyzing mechanical systems, particularly those utilizing crank and slider mechanisms.

ShaiNaveh
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Hi all,

I have a question regarding a simple crank and slider mechanism, but I'm not a mathematician. This means that long formulas scare me... (: I've been searching around and haven't found anything I can really understand.

I'm trying to get a "ball park" formula to calculate the amount of force I'll need to push plate B at a given angle between the two plates in order for them to fold. I suppose that when the angle is 180 deg., no force would do the trick, but at 0 deg it would be the easiest. I'm also sure it's not linear, but that's as far as my knowledge takes me for this kind of linkage...

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For this example let's say the the plates weigh 1kg each, and there is no friction involved. It's probably something you guys blurt out in your sleep, for me it's voodoo...Any help would be appreciated.

Many thanks, and happy September 1st holiday for us parents... (:
 
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Lengths of the plates?
 
Bystander said:
Lengths of the plates?
Ohhh dear, you're right, that IS important... It's 0.5m each.

Thank you.
 
Are you familiar with trig functions?
 
Bystander said:
Are you familiar with trig functions?
The basic stuff I suppose
 
Give you any ideas?
 
Bystander said:
Give you any ideas?
Not sure I understand what you mean...
Do trig functions give me any ideas, or are you asking me if I want you to give me any ideas...
 
ShaiNaveh said:
Do trig functions give me you any ideas
 
Yes, they give me an idea, but only an idea regarding the non-linear fashion of the force I need. As I said, I have a real problem with understanding formulas, all the way back to my school years. I've been designing and building machines for years using my experience and gut feeling when it comes to selecting motion components. So far nothing has crashed... but sometimes my gut feeling is not enough and I need to go back to school.

The way I see it, the mass is centered in the pivot. It should be half of each plate's mass when the angle is 180 deg., so there's 1kg to lift there. I also know that the pivot point gets easier to lift in a non-linear manner. It should be half the mass at 60 deg. if I'm not mistaken.
 

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