Create High frequency High voltage signal

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Creating a high frequency, high voltage signal of 1kV-5kV at 10MHz poses significant safety risks, especially for those without electronics expertise. OPAMPs typically do not support voltages above 200V, leading to the consideration of transformers as an alternative solution. It is suggested that using lower voltages may achieve the desired electric field without the associated dangers. The discussion emphasizes the importance of safety and proper resources when handling high voltage applications. Engaging with knowledgeable individuals or departments at a university is recommended for guidance.
BaasCR
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Hi all,

For my research I would like to create a high frequency high voltage signal. This signal should be in the order of 1kV-5kV with a frequency of around 10MHz. Can anyone help me with this? I'm not an electronic expert. I only have to apply the electric field, please note that I do not need to draw any current.

The OPAMP's I came across don't really amplify higher than 200V at maximum. Is it possible to create this signal by using transformers?

Thanks for the help!
 
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if you are not too good at electronics then I suggest for your safety you work on a project with much lower voltage.

Dave
 
BaasCR said:
Hi all,

For my research I would like to create a high frequency high voltage signal. This signal should be in the order of 1kV-5kV with a frequency of around 10MHz. Can anyone help me with this? I'm not an electronic expert. I only have to apply the electric field, please note that I do not need to draw any current.

The OPAMP's I came across don't really amplify higher than 200V at maximum. Is it possible to create this signal by using transformers?

Thanks for the help!

Welcome to the PF.

As stated, this is dangerous for a newbie to attempt. What department are you in at your university? What resources are available to you? What are you wanting to use this for? You can use a much lower voltage if you just want an electric field to fill a small volume. The units of electric field are Volts / meter, so you get the same E field with half the voltage across half the distance, and so on.
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

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