Creating Mohr's strain circle from a strain rosette

  • Thread starter Thread starter ridiculoid
  • Start date Start date
  • Tags Tags
    Circle Strain
Click For Summary
SUMMARY

This discussion focuses on calculating principal strains and stresses using Mohr's strain circle based on data from a strain rosette. The principal strains calculated are 122.5x10-6 and -296.5x10-6, leading to a Poisson's ratio of 0.413. The principal stresses derived are σx = 11.5 kPa and σy = -62.99 MPa. The accuracy of the Poisson's ratio is questioned due to insufficient information regarding the loading conditions.

PREREQUISITES
  • Understanding of Mohr's strain circle
  • Knowledge of principal strains and stresses
  • Familiarity with Poisson's ratio calculations
  • Basic proficiency in AutoCAD for graphical representation
NEXT STEPS
  • Study the derivation and application of Mohr's strain circle in detail
  • Learn about the implications of uniaxial loading on strain measurements
  • Research the significance of Poisson's ratio in material science
  • Explore the differences between plane stress and plane strain conditions
USEFUL FOR

Students and professionals in mechanical engineering, civil engineering, and materials science who are involved in strain analysis and stress calculations.

ridiculoid
Messages
18
Reaction score
0

Homework Statement


A sample is put in tension and a strain rosette gives the following results:
5JuhSP9.jpg

i) Calculate principal strains and poissons ratio using Mohrs strain circle.
ii) Calculate principal stresses from principal strains and poissons ratio.

Homework Equations


Mohr's strain circle
γ = -lateral strain / axial strain
σx = E / 1 - γ2 (εx + γεy)
σy = E / 1 - γ2 (εy + γεx)
E = 210 GPa

The Attempt at a Solution


I have drawn up Mohr's circle in autocad and found the following results.
lKhvdZx.jpg

principal strains = 122.5x10-6 & -296.5x10-6

poissons ratio = -122.5 / -296.5 = 0.413 (this seems too high?)

principal stresses = σx = 11.5kPa (this is supposed to be low as the load is applied in the y direction?)
σy = -62.99MPa (should this be negative if its in tension?)

Im hoping someone can tell me if I am on the right track.

Thanks in advance!
 

Attachments

  • 5JuhSP9.jpg
    5JuhSP9.jpg
    12.3 KB · Views: 934
  • lKhvdZx.jpg
    lKhvdZx.jpg
    22.4 KB · Views: 944
Physics news on Phys.org
Is this supposed to be plane stress or plane strain?
 
ridiculoid said:

Homework Statement


A sample is put in tension and a strain rosette gives the following results:
View attachment 231132
i) Calculate principal strains and poissons ratio using Mohrs strain circle.
ii) Calculate principal stresses from principal strains and poissons ratio.

Homework Equations


Mohr's strain circle
γ = -lateral strain / axial strain
σx = E / 1 - γ2 (εx + γεy)
σy = E / 1 - γ2 (εy + γεx)
E = 210 GPa

The Attempt at a Solution


I have drawn up Mohr's circle in autocad and found the following results.
View attachment 231133
principal strains = 122.5x10-6 & -296.5x10-6

poissons ratio = -122.5 / -296.5 = 0.413 (this seems too high?)

principal stresses = σx = 11.5kPa (this is supposed to be low as the load is applied in the y direction?)
σy = -62.99MPa (should this be negative if its in tension?)

Im hoping someone can tell me if I am on the right track.

Thanks in advance!
I confirm your principal strains. As far as the Poisson ratio is concerned, it seems that there is not enough information provided to determine it, unless the loading is uniaxial, and the principal strain in the z direction is also 122.5E-6.
 

Similar threads

  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 8 ·
Replies
8
Views
5K
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
15K
Replies
1
Views
6K
  • · Replies 1 ·
Replies
1
Views
8K
Replies
3
Views
5K
  • · Replies 3 ·
Replies
3
Views
9K