How is a Push Solenoid Constructed Differently from a Pull Solenoid?

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Push and pull solenoids differ primarily in the attachment method of the plunger, with pull solenoids typically having a hook on one end and push solenoids featuring a pushpin. The construction involves a copper wire wound around a tube, and the plunger moves within the coil when activated, affecting the magnetic energy. The plunger's movement is always from left to right, with its passive position skewed to the coil's center. Understanding the load for each type of solenoid can help clarify their practical applications. The distinction in construction and functionality is essential for effective design and use in various projects.
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I was reading http://www.rossdecco.com/pdf/how_a_dc_solenoid_works.pdf about push and pull solenoids. I don't quite understand what differentiates the two in terms of construction. What I have is a copper wire wound around a tube and the ends are attached to a battery, like in this I believe in this video it is a pull solenoid. How is the push constructed differently from the pull exactly? What can I do to construct that same thing seen in the video into a push type? Is it just a matter of length of the plunger?
 
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The only difference is whether a hook is attached to the left side of the plunger, or if a pushpin is attached to the right side.

The plunger itself is always moving from left to right when activated, because the plunger will take up more volume within the coil, when doing so. The "passive" position is skew to the center of the coil.

By seeking toward the center of the coil, the plunger will weaken the energy in the magnetic energy, Emagn , as much as possible. Placing an x-axis along the center axis of the coil, the force yielded by the plunger will be:

F = dEmagn / dx
 
Last edited:
Hesch said:
The only difference is whether a hook is attached to the left side of the plunger, or if a pushpin is attached to the right side.

The plunger itself is always moving from left to right when activated, because the plunger will take up more volume within the coil, when doing so. The "passive" position is skew to the center of the coil.

By seeking toward the center of the coil, the plunger will weaken the energy in the magnetic energy, Emagn , as much as possible. Placing an x-axis along the center axis of the coil, the force yielded by the plunger will be:

F = dEmagn / dx
Hm, that's helpful to understand. Though, a better question to ask now is what would the load be in both cases (an example of what would be)?
 
I do not have a good working knowledge of physics yet. I tried to piece this together but after researching this, I couldn’t figure out the correct laws of physics to combine to develop a formula to answer this question. Ex. 1 - A moving object impacts a static object at a constant velocity. Ex. 2 - A moving object impacts a static object at the same velocity but is accelerating at the moment of impact. Assuming the mass of the objects is the same and the velocity at the moment of impact...

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