Critical numbers of this derivative

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SUMMARY

The function under discussion is \(y = \sqrt{x} - 4\ln(x)\). The derivative is calculated as \(y' = \frac{{\sqrt{x} - 8}}{{2x}}\). Critical numbers are determined by setting the derivative equal to zero or identifying where it is undefined. The critical number found is \(x = 64\), while \(x = 0\) is excluded as it is not in the domain of the original function, confirming that critical points refer to the original function \(y\), not its derivative.

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opticaltempest
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I have the function [tex]\[y = \sqrt x - 4\ln (x)\][/tex]

I find the derivative to be [tex]\[y' = \frac{{\sqrt x - 8}}{{2x}}\][/tex]

When finding the critical numbers of y' I look for where the derivative
is equal to zero or where the derivative is undefined. So where y' is
equal to zero is when x=64. y' is undefined when x=0, but when x=0
the original function is also undefined. Since x=0 makes the original
function undefined can I exclude it from my critical points? I am thinking
I am able to since x=0 isn't even in the domain of y.

Thanks
 
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Yes, that is correct. By the way, the phrase "critical numbers of y' " is not correct. What you have found are the critical numbers of y itself, not its derivative.
 
Thanks HallsofIvy :smile:
 

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