Critically damped oscillator: Classical mechanics help

[Theorem.]

Homework Statement

A critically damped oscillator with natural frequency \omega starts out at position x_0>0. What is the maximum initial speed (directed towards the origin) it can have and not cross the origin?

Homework Equations

For the case of critical damping,
x(t)=e^{(-\gammat)}(A+Bt) where \gamma=\omega=\sqrt{k/m}

The Attempt at a Solution

Well first I derived the above equation (and verified it with my textbook). I then evaluated the initial position:
x(0)=A.
I then took the derivative of the position function to get velocity:
v(t)=(e^{-\gamma t}) ( B-Bt\gamma -A\gamma)
Setting t=0 I obtained
v(0)=B-A\gamma recalling that x₀=A, v(0)= B-x_0\gamma. I then solved for Beta: B=v_0 +\gamma x_0.
I then tried substituting this back into the position equation, and solving for the initial velocity, the program is there is always time dependency that i can't get rid of... what am i doing wrong? any advice would be much appreciated!
Thanks

 

[Theorem.]

umm its supposed to be e^-tgamma(B-Bt(gamma)-A(gamma)) for the velocity and v(0)=B-A(gamma)=B-x_0(gamma) for the initial velocity
and x(t)=e^-tgamma(A+Bt) for the position but for some reason I all the sudden fail at latex

 

[splogia]

I think I solved it... you're on the right track. Solve for x(t) in terms of gamma, w, Xo and Vo, then make x(t)=0 and solve for Vo. Next, derive V(t) by taking dx/dt (remember to include initial conditions!). Take the limit as t goes to inf of V(t), and substitute terms so that you're left with w and Xo, and you should get Vmax.