Crystal frames problem, what actually asking?

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SUMMARY

The discussion revolves around a problem from the Sterway and Jewett physics textbook concerning the calculation of the distance between atomic spheres, specifically yielding a result of 0.141 nm. The original poster expressed confusion over the problem's requirements and the relevance of the distance measurement. Ultimately, they resolved the issue independently using a self-made school board, indicating that visual aids can significantly enhance understanding of complex concepts.

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  • Understanding of atomic structure and distances between atomic spheres
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  • Study the concept of atomic distances in solid-state physics
  • Learn about geometric representations in physics problems
  • Explore additional problems in the Sterway and Jewett textbook for practice
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Students studying physics, educators seeking teaching strategies, and anyone looking to improve their problem-solving skills in atomic structure and geometry.

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Homework Statement



The problem from Sterway, Jewett book.

Serway_Jewett_problem_Mech_Crystal1.jpg


Serway_Jewett_problem_Mech_Crystal2.jpg


The Attempt at a Solution



The answer in the book is something like 0,141 nm, as I remembered but I cannot achieve such answer coz' I cannot understand what actually asking, d is looks like a distance between two centers of the atomic spheres, but I don't think that it can be 0,141 nm, probably due to my English language, so can somebody clarify for little bit, what the hell I need to find in this problem. I am stucked for now, and my brain will start to melt soon. And imho - this book have too much of unnecessary problem, 70 problem for the first chapter is too much... Thanx.
 
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In the same way as the distance between vertical or horizontal planes is L, the distance between the 45 degree planes is ##{1\over 2}\sqrt 2 ## L. Easiest seen in a side view:
upload_2017-5-5_16-15-39.png
 
BvU said:
In the same way as the distance between vertical or horizontal planes is L, the distance between the 45 degree planes is ##{1\over 2}\sqrt 2 ## L. Easiest seen in a side view:
View attachment 198771
Or this picture in the book is distracting, or frostysh is just too dull :), anyway I have solved the problem on my new cool self-made school-board, and now I am very happy ^^. Thanx again, Solved.
 

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