Curl of Polarization in a bar electret

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In Griffith's "Introduction to Electrodynamics" says that in a bar electret the curl of the polarization does not equal zero everywhere. Why is that ? Thanks in advance
 
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What comes to mind very quickly is the corresponding magnetostatics problem with a cylinder of uniform magnetization ## \vec{M} ##. In that case, ## \nabla \times \vec{M} =\vec{J}_m ## results in surface currents per unit length of ## \vec{K}_m=\vec{M} \times \hat{n} ## on the surface of the cylinder. ## \\ ## In the simplest case of uniform ## \vec{ P} ##, if you take ## \nabla \times \vec{P} ##, you will get places where ## \nabla \times \vec{P } ## diverges at parts of the surface/air interface. In general, if ## \vec{P} ## is uniform, the derivative ## \nabla \times \vec{P} ## vanishes, but this derivative can diverge when ## \vec{P} ## undergoes a discontinuity such as at the surface/air interface.
 
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Thank you, it is pretty clear for me now that at the surface/air interface will have ##\nabla \times \vec{P} \neq 0 ##. Then Griffiths continues and says that "if the problem exhibits spherical, cylindrical, or plane symmetry then evidently in such cases ##\nabla \times \vec{P} = 0 ##." So what does he mean about cylindrical symmetry and why a bar electret is not such a case ?
 
Griffith's seems to be talking about the polarization ## \vec{P} ## in the material, and not considering edge effects. It is well known from E&M, that in the case of a dielectric sphere in a uniform electric field, the polarization inside the sphere is uniform. This also is the case for a cylinder that is transverse to the electric field. I'll see if I can find a couple of "links" to these very special cases. In general, for odd geometries, the resulting polarization ## \vec{P} ## is not uniform when the dielectric object is placed in uniform electric field, and consequently, the derivative ## \nabla \times \vec{P} ## does not vanish. Let me try to find a couple of "links" on the two special dielectric geometries: See: https://www.physicsforums.com/threads/electric-field-of-a-charged-dielectric-sphere.890319/ and https://www.physicsforums.com/threa...ormly-polarized-cylinder.941830/#post-5956930
 
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