Current induced in loop - treat like a solenoid?

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SUMMARY

The discussion revolves around calculating the induced current in a circular loop of wire due to a nearby straight wire carrying a constant current of 10A. The magnetic field (B) at the center of the loop is derived using the formula B = μi / 2πr, where μ is the permeability of free space and r is the distance from the wire. The induced current in the loop is determined to be approximately 2.71A, flowing counterclockwise, based on the assumption of uniform magnetic field and treating the loop similarly to a solenoid.

PREREQUISITES
  • Understanding of electromagnetic principles, specifically Ampère's Law.
  • Familiarity with magnetic field calculations using B = μi / 2πr.
  • Knowledge of solenoid behavior and its magnetic field equations.
  • Basic concepts of induced current and Lenz's Law.
NEXT STEPS
  • Study the derivation and applications of Ampère's Law in different configurations.
  • Learn about the principles of electromagnetic induction and Lenz's Law.
  • Explore the characteristics of solenoids and their magnetic fields in detail.
  • Investigate the effects of varying current in nearby conductors on induced currents.
USEFUL FOR

Students and educators in physics, electrical engineers, and anyone interested in understanding electromagnetic induction and its applications in circuit design.

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Homework Statement



A long straight wire lies below to a circuluar loop of wire. The straight wire is carrying a constant 10A current to the right. What is the magnitude and direction of the current in the circular loop, if its diameter is 1 m and its center is 0.75m away from the wire


Homework Equations



B = u i / 2pir

B = u i N for solenoid


The Attempt at a Solution



B = ui/2pir
since current in wire is traveling right and the loop is above the wire, the magnetic field on the loop is going to be coming out of the screen, I'm going to assume that the magnetic field is uniform, using the distance from the center as the radius, even though.. that is probably a bad assumption?

so the current will travel counterclockwise

can't figure out how to find the magnitude though! should i be treating it like a solenoid, and plug in the magnetic field to get a current?
 
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B = ui/2pir = (4pix10^-7)(10)/2pi(0.75)= 0.213 TB = uiN N = 4pix0.75/2pi = 0.47 turnsI = B/uN= (0.213 T)/(4pix10^-7 x 0.47 turns)= 2.71 A
 

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