- #1

ninjadrummer8

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## Homework Statement

Ok guys, this problem has a few steps to it, and id appreciate any help I can get.

Ok, so beam of electrons moving left, positive particles with same but opposite charge moving right, both moving at 1x10^8 m/s. Then there is a proton moving left on top of the beam nearby AT ALSO 1x10^8 m/s. A person standing nearby is observing, and so is a guy running ALSO 1x10^8 m/s nearby.

**Questions:**

1) Direction of current?

2) Force on the proton as seen by the person standing, and the person running seperatly.

3) Velocity/direction of the two beams from the running persons point of view?

4) What current will the man running measure and in which direction?

## Homework Equations

1) none

2) F=qvBsin(theta) (or in this case just F=qvB since the direction of the proton is perpendicular to the magnetic field..?)

3) none

4) ?

## The Attempt at a Solution

1) Current flows is opposite of current flow, so therefore in this case current flows to the right. Is this correct?

2) Person standing still: There is a magnetic field flowing out of the screen from the view we have, if the current is indeed traveling to the right. Therefore, I simply use the equation F=qvB to solve.

**Is this true, or would I need to factor in the fact that the electrons are also drawing the particle towards them?**

Person running: since he is moving at the same speed and direction as the proton, it will seem to him that it is not moving.

3) The beam moving in the same direction will seem as though it doesn't move, but the beam moving in the opposite direction will seem to move twice as fast.

4) will he measure no current? since he is moving as fast as the electrons?Thanks for any help guys! I appreciate it.

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