Cutoff Point for Relativistic Effects

In summary, the Lorentz factor is a dimensionless constant that is used to adjust for relativistic effects in various equations, such as length contraction and time dilation. It is extremely close to 1 for speeds below 3\cdot10^7\frac{m}{s} and only becomes significant for speeds close to the speed of light. It is also used in the Lorentz transformations and can be considered a measure of the importance of relativity in a given situation.
  • #1
pzona
234
0
I'm looking over some common physics equations as a review for the course I'll be taking next semester, and for each equation, I'm coming across two equations for each, a relativistic and a non relativistic. The class I'll be taking will be on mechanics, inertia, etc., so I figure I'll only need to know the nonrelativistic equations. I'm just curious though, at what velocity do you start taking relativistic effects into account? Is there an accepted cutoff point, or do you just judge it based on the problem? Thanks in advance for any help with this
 
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  • #2
I generally use .1c as the cutoff point for relativistic corrections. At this velocity, the difference between the result a relativistic and non-relativistic formula will give starts to be within the number of significant digits of the problem.
 
  • #3
Yes, there's no way you'll need relativistic equations for the mechanics of bodies.

You'ld only need it for particles (eg a photon colliding with an electron).
 
  • #4
You can use the Lorenz factor [tex]\gamma=\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}[/tex] to check how prominent relativistic effects are. For velocities way below c, it is very close to 1, and it will say around 1 for velocities up to maybe [tex]3\cdot10^7\frac{m}{s}[/tex], like Nabeshin suggested. For example, at v=0.1c, the Lorentz factor is about 1.005.
 
  • #5
I think most people usually refer to the "extreme relativistic limit" as the point where a particle's momentum is much greater than its mass, and the "non-relativistic limit" as when the momentum is much smaller than the mass. This comes from the relativistic energy formula:

[tex]E = \sqrt{(pc)^2+(mc^2)^2}[/tex]

We can see that when [itex]pc>>mc^2[/itex], it just becomes [itex]E = pc[/itex]. It's often convenient to work in this regime when doing quantum or stat mech calculations, because you've got a Hamiltonian that goes linearly with momentum. When [itex]pc<<mc^2[/itex], we can do a Taylor expansion on p,

[tex]E \approx mc^2 + \dfrac{p^2}{2m}[/tex]

You can see that the only two terms left are the rest energy term and the Newtonian kinetic energy, so now you can just use non-relativistic mechanics. This, by the way, is one of the ways to get the famous formula [itex]E = mc^2[/itex]. When you use relativity to get a non-relativistic limit, you end up with something left over besides the kinetic energy.

When the momentum and mass are approximately the same, you can't really use any approximations, and this is when all the usual relativistic formulas apply.
 
  • #6
espen180 said:
You can use the Lorenz factor [tex]\gamma=\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}[/tex] to check how prominent relativistic effects are. For velocities way below c, it is very close to 1, and it will say around 1 for velocities up to maybe [tex]3\cdot10^7\frac{m}{s}[/tex], like Nabeshin suggested. For example, at v=0.1c, the Lorentz factor is about 1.005.

I have a question: What does the Lorentz Factor mean? I know that it comes out to be a dimensionless constant, but that role does that constant play? What does it mean?
 
  • #7
KrisOhn said:
I have a question: What does the Lorentz Factor mean? I know that it comes out to be a dimensionless constant, but that role does that constant play? What does it mean?

It's the factor that you put in front of many mechanical quantities to adjust for relativistic effects. For example, the length contraction formula is [itex]L=\gamma L'[/itex], the time dilation formula is [itex]dt = \gamma dt'[/itex], the relativistic momentum is [itex]p = \gamma mv[/itex], etc. It also appears in the Lorentz transformations. For even large speeds, the gamma factor is extremely close to 1. Only at speeds very close to the speed of light does it become important, and at speeds above .99c, even small increases in velocity correspond to very large changes in the gamma factor. Basically it's a measure of how important relativity is.
 
  • #8
arunma said:
It's the factor that you put in front of many mechanical quantities to adjust for relativistic effects. For example, the length contraction formula is [itex]L=\gamma L'[/itex], the time dilation formula is [itex]dt = \gamma dt'[/itex], the relativistic momentum is [itex]p = \gamma mv[/itex], etc. It also appears in the Lorentz transformations. For even large speeds, the gamma factor is extremely close to 1. Only at speeds very close to the speed of light does it become important, and at speeds above .99c, even small increases in velocity correspond to very large changes in the gamma factor. Basically it's a measure of how important relativity is.

Thank you, that makes sense.
 
  • #9
Now that you mention the Lorenz Factor, it was showing up in a few different places (relativistic momentum, etc.) while I was trying to review equations, and I didn't know what it was. That makes sense that it can be considered a factor itself though. Thanks for the help everyone
 
  • #10
espen180 said:
You can use the Lorenz factor

At the risk of being pedantic, it's "Lorentz", as in Hendrik Lorentz, not "Lorenz", as in Ludvig Lorenz. (Of course the Lorentz–Lorenz equation works in either order!)
 

Related to Cutoff Point for Relativistic Effects

What is the cutoff point for relativistic effects?

The cutoff point for relativistic effects is typically considered to be when the speed of an object approaches 10% of the speed of light, or approximately 30,000 km/s. At this point, the effects of relativity become significant and can no longer be ignored.

What are some examples of relativistic effects?

Some examples of relativistic effects include time dilation, length contraction, and mass-energy equivalence. These effects occur at high speeds and can be observed in experiments such as the famous "twin paradox".

How do relativistic effects impact our daily lives?

In our daily lives, relativistic effects are not noticeable due to the relatively low speeds that we encounter. However, they do play a crucial role in technologies such as GPS, which relies on precise timing and takes into account the time dilation caused by the satellites orbiting at high speeds.

Can relativistic effects be ignored in scientific calculations?

In most cases, relativistic effects can be ignored in scientific calculations as they only become significant at very high speeds. However, in fields such as particle physics and astrophysics, these effects must be taken into account for accurate results.

How does the cutoff point for relativistic effects vary for different objects?

The cutoff point for relativistic effects varies for different objects depending on their mass and velocity. For example, a spacecraft traveling at a relatively high speed may experience relativistic effects, while a human walking at the same speed would not. The cutoff point also varies for different particles, with lighter particles experiencing relativistic effects at lower speeds compared to heavier particles.

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