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Cyclotron accelerating protons to 20 MeV with potential gap 100 kV

  1. Jul 17, 2008 #1
    1. The problem statement, all variables and given/known data
    A Cyclotron is accelerating proton, where the applied magnetic field is 2 T, the potential gap is 100 KV, then how much turn are required for a kinetic energy of 20 MeV....

    (a) 300
    (b) 200
    (c) 150
    (d) 100
     
  2. jcsd
  3. Jul 18, 2008 #2
    Re: Cyclotron

    20MeV is around when relativistic effects take place. The voltage alternates periodically. After one turn (or half a turn--semicircle...I'm not sure) the proton gains a kinetic energy of qV, V being the potential gap. Using that value, find out how many turns it takes to total 20MeV.
     
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