Cylinder about side, finding angular velocity

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Homework Help Overview

The discussion revolves around a problem involving a rotating cylinder, specifically a disk that rotates about an axle at one edge. The scenario describes the disk's release from a height and seeks to determine its angular velocity when it is directly below the axle.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of conservation of energy principles, questioning the relationship between potential energy and rotational kinetic energy. There is mention of moment of inertia and its relevance to the problem setup.

Discussion Status

Some participants have provided guidance on using rotational energy in conjunction with potential energy. There is an acknowledgment of the need to calculate the moment of inertia about the pivot point, indicating a productive direction in the discussion.

Contextual Notes

Participants are navigating the complexities of applying rotational dynamics and energy conservation, with some initial confusion regarding the correct approach to the problem. The original poster's attempts to treat the situation like a pendulum are noted as a point of clarification.

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Cylinder about side, finding angular velocity...

Homework Statement



A 5.0 kg, 60-cm-diameter disk rotates on an axle passing through one edge. The axle is parallel to the floor. The cylinder is held with the center of mass at the same height as the axle, then released.

http://session.masteringphysics.com/problemAsset/1001021/11/knight_Figure_13_72.jpg

What is the cylinder's angular velocity when it is directly below the axle?

Homework Equations



Law of conservation of energy (kinetic and potential of both sides)

The Attempt at a Solution



I tried to do this problem using mgy=1/2mv^2 but it didnt work...

I know it has something to do with moment of inertia, but do I just add the moment of inertia to the 1/2mv^2 and solve for v?
 
Last edited:
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I tried to do this problem using mgy=1/2mv^2 but it didnt work...
Use rotational energy with the potential energy. The initial rotation energy about the axle is zero, so all the potential energy must go into rotational energy at the bottom point.
I know it has something to do with moment of inertia, but do I just add the moment of inertia to the 1/2mv^2 and solve for v?
You do not just "add" in moment of inertia! You will need to find the moment of inertia of the disk about that pivot point.
 
ah ic, i need to use rotational energy...i was treating this as a pendulum but i guess i can't do that haha

lol yea, that's what i meant, i have to use Icm + Md^2 to find it at the pivot point

thanks, ill see how it goes
 
Last edited:
yo thanks, i got it!
 

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