Cylindrical Coordinates Triple Integral -- stuck in one place

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SUMMARY

The discussion focuses on evaluating a triple integral using cylindrical coordinates for the solid defined by the cylinder \(x^2+y^2 = 9\), above the plane \(z=0\) and below the plane \(z=5-y\). The correct bounds for the triple integral are established as follows: \(d\theta\) ranges from \(0\) to \(2\pi\), \(dr\) ranges from \(0\) to \(3\), and \(dz\) is determined to be from \(0\) to \(5 - r\sin(\theta)\). The participants emphasize that the bounds apply to the coordinates rather than the differentials.

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Homework Statement


Use cylindrical coordinates to evaluate triple integral E (sqrt(x^2+y^2)dv where E is the solid that lies within the cylinder x^2+y^2 = 9, above the plane z=0, and below the plane z=5-y

Homework Equations

The Attempt at a Solution


So i just need to know how to get the bounds for the dz and i have everything else.

triple integral dtheta bound: 0 to 2pi, dr bound 0 to 3, and not sure if the dz bound is 5-rsintheta?
 
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fhot112 said:
and not sure if the dz bound is 5-rsintheta?
What is your argument for this and what makes you uncertain of your argument?

Also, for clarity, the bounds are on the coordinates themselves, not on the coordinate differentials.
 

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