Is the Triple Integral in Cylindrical Coordinates Correctly Solved?

In summary, the conversation discusses the use of cylindrical coordinates to solve a problem involving a region E and the evaluation of its volume. There is some confusion about the boundaries of integration and whether the method used is correct. The summary also mentions a correction made by one of the speakers and confirmation that the solution is correct. The conversation ends with a statement about 1008 being divisible by 3.
  • #1
daphnelee-mh
66
4
Homework Statement
(question is attached below)
Relevant Equations
x^2+y^2=r^2
dV=rdrdzdΘ
1593762965635.png


1593762987337.png


I am trying to solve it using cylindrical coordinates, but I am not sure whether the my description of region E is correct, whether is the value of r is 2 to 4, or have to evaluate the volume 2 times ( r from 0 to 4 minus r from 0 to 2), and whether is okay to take z from r^2/2 to 8
 
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  • #2
[tex]\int_2^8 dz \int_0^{2z} 2\pi \rho^3 d\rho[/tex]
 
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  • #3
May I know which method did you use? I have no idea of it, thanks
 
  • #4
Find attached my handwriting.
 

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  • #5
anuttarasammyak said:
[tex]\int_2^8 dz \int_0^{2z} 2\pi \rho^3 d\rho[/tex]
Shouldn't the boundary of integration be ##\sqrt{2z}## instead of ##2z##?
 
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  • #6
Yes. Thanks for correction.
 
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  • #7
1593775272308.png

Can you help to see whether this is correct ? Thank you
 
  • #8
Yes it looks correct to me.
 
  • #9
Thank you so much
 
  • #10
daphnelee-mh said:
View attachment 265726
Can you help to see whether this is correct ? Thank you
The digits of 1008 add to 9, so...
 
  • #11
haruspex said:
The digits of 1008 add to 9, so...
?
 
  • #12
daphnelee-mh said:
?
So 1008 is divisible by 3.
 
  • #13
haruspex said:
So 1008 is divisible by 3.
okay , thank you
 
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