Damped Oscillator Conceptual Problem and Differential Equation Solution

  • Thread starter Thread starter ggilvar99
  • Start date Start date
  • Tags Tags
    Damped Oscillator
Click For Summary
The discussion revolves around a damped oscillator system consisting of a mass connected to a spring with viscous damping. The user is trying to formulate the differential equation for horizontal oscillations based on given observations about static compression and resistive forces. They express confusion about translating the viscous force into a comprehensive differential equation for all velocities. Suggestions are made to derive the spring constant (k) and damping coefficient (λ) from the conditions provided, leading to a clearer understanding of the problem. The conversation emphasizes the importance of correctly applying the relationships between forces and motion in deriving the necessary equations.
ggilvar99
Messages
6
Reaction score
0
Hey guys I'm new to the forum and having a little trouble with this conceptual problem.

1. A block of mass m is connected to a spring, the other end of which is fixed. There is also a viscous damping mechanism. The following observations have been made of this system:

i) If the block is pushed horizontally with a force equal to mg, the static compression of the spring is equal to h

ii) The viscous resistive force is equal to mg as the block moves with a speed u.


a) Write the differential equation governing horizontal oscillations of the mass in terms of m, g, h and u.

b) for the particular case of u = 3√gh, what is the angular frequency of the damped oscillations?


2. Homework Equations :

mx'' + λx' + kx = 0


3. The Attempt at a Solution :

F = mg = -kh (x = h)

F = mg = -λu for x' = u

At this point I'm somewhat lost and not sure what they're looking for. If the viscous force = mg at velocity u, how can you translate that into a differential equation that covers all velocities of the mass? Any help would be greatly appreciated
 
Physics news on Phys.org
Can you obtain express ##k## and ##\lambda## from the conditions given?
 
Oh, you're saying to set k = -(mg)/h and lambda = -(mg)/u and plug that into the diffeq? I don't know why that never occurred to me, thanks a lot for the suggestion!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
2
Views
2K
Replies
9
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
13
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
3
Views
841
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K