Dartmouth Extended Laplace Tables -- Not general enough? item26.a

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SUMMARY

The discussion centers on the application of the Extended Laplace Transform Table, specifically item 26a, in solving the homogeneous solution for an underdamped second-order dynamic system with non-zero initial conditions. The user encounters inconsistencies in the magnitude calculations when applying the formula from the table, leading to suspicions about the correctness of item 26a. The derived expressions for the magnitude do not align with expected results, prompting a reevaluation of the dimensionality of the constant alpha and its implications on the formula's validity.

PREREQUISITES
  • Understanding of second-order dynamic systems and their characteristics.
  • Familiarity with Laplace transforms and their applications in differential equations.
  • Knowledge of damping ratios and natural frequencies in mechanical systems.
  • Basic algebraic manipulation skills for solving equations involving complex variables.
NEXT STEPS
  • Review the derivation of the Laplace transform for second-order systems.
  • Investigate the properties and applications of the Extended Laplace Transform Table.
  • Examine the dimensional analysis of constants in dynamic systems, focusing on alpha and zeta.
  • Explore alternative methods for solving underdamped system equations to validate findings.
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ltkach2015
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Homework Statement


[/B]
http://www.dartmouth.edu/~sullivan/22files/New%20Laplace%20Transform%20Table.pdf
(see item 26a)

homogenous solution to underdamped in amplitude phase form: (see attached image)

2. Relevant info

- non zero initial conditions: x(t=0) = xo AND dx/dt(t=0) = vo
- unforced motion: F(t) = 0
- second order dynamic system (1DOF & in one dimension x)
- ODE and final solution is written in terms of damping ratios (z), and natural frequencies (wn)
- damping frequency: wd = wn*sqrt(1-z^2)
-Underdamped system: |z| < 1

The Attempt at a Solution



-Given
d^2x/dt^2 + 2*z*wn*dx/dt + wn^2*x = 0

-Now I take laplace

[X(s)*s^2 - s*xo - vo] + 2*z*wn*[X(s)*s - xo] + wn^2*X(s) = 0

-Algebra

X(s) (s^2+2*z*wn*s+wn^2) = s*xo + vo + 2*z*wn*xo

-Solving for X(s)

X(s) = [s*xo + vo + 2*z*wn*xo] / [s^2 + 2*z*wn*s + wn^2]

More algebra so that I may use item 26a in the extended Laplace tables

X(s) = xo*[ s + (vo+2*z*wn*xo)/xo ] / [s^2+2*z*wn*s+wn^2]I will define alpha (as listed in the Extended Laplace Table item 26a):

alpha = (vo+2*z*wn*xo)/xo

When I directly apply this formula from the Extended Laplace Tables I get an inconsistent answer (see attached)

Just looking at the Magnitude (magnitude is off)

sqrt{ [( alpha/wn - z*wn )^2] / (1-z^2) + 1 }

Replacing alpha with (vo+2*z*wn*xo)/xo

= sqrt{ [ [(vo+2*z*wn*xo)/xo)/wn - z*wn]^2/(1-z^2) + 1 }

Making common denominator, and making 1-z^2 = (wd/wn)^2

= sqrt{ [vo+2*z*wn*xo]/(xo*wn) - z*wn^2*xo/(xo*wn)]^2/ (wd/wn)^2 + 1}

Bringing up wd/wn into the square & notice wn and 1/wn cancel

Factor out 1/xo^2

= sqrt{ [vo+2*z*wn*xo] - z*wn^2*xo]^2/ (wd*xo)^2 + }

Making 1 have common denominator with other stuff

= sqrt{ [vo+2*z*wn*xo] - z*wn^2*xo]^2/ (xo*wd)^2 + 1*(xo*wd)^2/(xo*wd)^2 }

Factor out 1/(xo*wd)

= 1/(xo*wd)* sqrt{ [vo+2*z*wn*xo] - z*wn^2*xo]^2 + (xo*wd)^2}

This magnitude (just above) does not agree with the correct magnitude (next couple of lines) (can also see attached source):

= 1/(xo*wd)* sqrt{ [vo+2*z*wn*xo - z*wn*xo]^2 + (xo*wd)^2}

= 1/(xo*wd)* sqrt{ [vo+z*wn*xo ]^2 + (xo*wd)^2}

I believe that item 26a may not be general enough. As the z*wn term within the square that's within the square root should just be zQUESTION:

What's going on on here? Thank you.
 

Attachments

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I'm actually a little suspicious that the entry 26a in the table might not even be correct at all.

Unless I'm making a large mistake myself, here is my logic:

I suspect that the constant \alpha should have dimensionality of \frac{1}{[\mathrm{time}]}. (Again, that is if I'm not mistaken). If so, then one of the terms in 26a doesn't make sense to me: in particular, the part of term that is \frac{\alpha}{\omega_n} - \zeta \omega_n.

\omega_n also has units of \frac{1}{[\mathrm{time}]}. That makes \frac{\alpha}{\omega_n} dimensionless (if I'm correct about \alpha), and \zeta is dimensionless. But that gives \zeta \omega_n dimensionality of \frac{1}{[\mathrm{time}]}. So that operation is subtracting a \frac{1}{[\mathrm{time}]} value from a dimensionless number.

With that I conclude (or at least suspect) that something doesn't look right with 26a to me.
 
Yes I agree the dimensions do look off
 

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