Advanced Circuits, Laplace Transform, Find Initial Conditions

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SUMMARY

The discussion focuses on the analysis of the Laplace Transform for the circuit equation Vo(S) = [N(s)Vi(s) + (-s^2 + s - 2)] / (s^3 + s^2 + 1). Participants emphasize the importance of using the correct notation, specifically v(t) instead of V(t) and lower-case s for the Laplace variable. The conversation highlights the need to equate initial conditions v(0+) and its derivatives with the terms derived from the equation, avoiding partial fraction expansions. The right-hand side of the equation is simplified to L-1{Vi(s)N(s)} without concern for N(s).

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  • Understanding of Laplace Transforms and their applications in circuit analysis
  • Familiarity with differential equations and their solutions
  • Knowledge of initial conditions in the context of Laplace Transforms
  • Proficiency in algebraic manipulation of rational functions
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  • Study the process of equating initial conditions in Laplace Transforms
  • Learn about the implications of using partial fraction expansion in circuit analysis
  • Explore the concept of inverse Laplace Transform and its applications
  • Investigate the significance of notation in mathematical expressions, particularly in Laplace analysis
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Electrical engineers, circuit designers, and students studying control systems or circuit analysis who seek to deepen their understanding of Laplace Transforms and initial conditions in circuit equations.

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Homework Statement
For a circuit, applying Laplace transform, the output is related to input by:

V_o(S)=(N(s) V_i(s) - s^2+s-2)/D(s),

where D(S) = (s^3 + s^2 + 1).

Find ALL initial conditions (there is no need to know N(s) ).
Relevant Equations
Partial Fraction Expansion, Laplace Transforms:
d^n x(t) / dt^n <---> s^n X(S) - s^n - 1x(0-) – s^(n-2)x'(0-) – s^(n-3)]x''(0-) ….
dx(t)/dt <---> sX(s) – x(0-)

d^2x(t)/dt^2 <---> s^2X(s) – sx(0-) – x/(0-)
Vo(S) = [ N(s)Vi(s) + (- s2 + s - 2) ] / s3 + s2 + 1 ;

can ignore (-s^2 + s - 2).

From relevant equations:

Vo(S) = [N(s)*Vi(s)]/(s^3 + s^2 + 1); -> (d3Vo(t)/dt3) + (d2Vo(t)/dt2) + Vo(t) = N(t)(dvi)/dt

L[vi(t)] = t to s domain: [s3Vo(s) - s2Vo(0-) - SV'o(0-) - Vo''(0-)]Vo(s) + s2 - SVo - V'o(0)] Vo(s) + Vo(s) = N(Vi)(s)

= [s3 V(s) - s2 + s + 2] V0(s) + [s2 - s - 1]V0(s) + V0(s) = N(Vi(s))

I'm sort of lost simplifying this now. I know I'm supposed to set up for partial fraction expansion eventually but not sure how.
 
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Color_of_Cyan said:
Vo(S) = [ N(s)Vi(s) + (- s2 + s - 2) ] / s3 + s2 + 1 ;

can ignore (-s^2 + s - 2).

From relevant equations:

Vo(S) = [N(s)*Vi(s)]/(s^3 + s^2 + 1); -> (d3Vo(t)/dt3) + (d2Vo(t)/dt2) + Vo(t) = N(t)(dvi)/dt
This is a good start but where did you get the right-hand side? It's just L-1{Vi(s)N(s)} so leave it at that. You will not be concerned with N(s) in any way anyway.

NOTE: You should use v(t) instead of V(t). Don't confuse the two. Also, always use lower-case s fot the Laplace variable, not S.

Also, the initial condition is v(0+), not v(0-) etc.

You have the right idea equating v(0+), v'(0+) etc. with the given terms not functions of N(s). But now I've kind of lost you. Don't use partial fraction expansions.

Equate like powers of s to your given terms & solve for v(0+) and the necessary additional derivatives of v(0+).
 

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