DC Shunt Generator: Armature Current, Terminal Voltage & Efficiency

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SUMMARY

The discussion focuses on calculating the armature current, terminal voltage, and efficiency of a DC shunt generator with specific parameters: armature resistance of 0.8Ω, field winding resistance of 120Ω, mechanical loss of 115W, and load resistance of 8.5Ω. The generator operates at a speed of 1670rpm with a back e.m.f. constant of 0.86Vs/rad. Participants confirm the use of the voltage divider formula and equivalent circuit analysis to derive the terminal voltage and armature current, emphasizing the importance of combining resistances correctly.

PREREQUISITES
  • Understanding of DC shunt generator operation
  • Knowledge of equivalent circuit analysis
  • Familiarity with voltage divider principles
  • Ability to calculate back electromotive force (e.m.f.)
NEXT STEPS
  • Learn how to calculate armature current in DC circuits
  • Study the effects of mechanical losses on generator efficiency
  • Explore the application of the voltage divider formula in electrical circuits
  • Investigate the significance of back e.m.f. in generator performance
USEFUL FOR

Electrical engineering students, professionals working with DC machines, and anyone involved in the analysis and optimization of generator performance.

TimWillz
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Homework Statement


A shunt generator has an armature resistance of 0.8Ω, a field winding resistance of 120Ω and a mechanical loss of 115W. The load resistance of 8.5Ω is connected to the output terminals of the generator. An external mover rotates the shaft of the generator at a speed of 1670rpm. If a back e.m.f. constant of the generator is 0.86Vs/rad calculate:

a) armature current
b) terminal voltage
c) efficiency

I really can't get going on this question, can anyone help me out?


Homework Equations





The Attempt at a Solution

 
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Is there any way to find a voltage from the back e.m.f.?
 
TimWillz said:
Is there any way to find a voltage from the back e.m.f.?

Yes there is. Can you draw the equivalent circuit? You have the internal EMF with the armature resistance in series, and then both the field resistance and load resistance in parallel to complete the circuit. The terminal voltage is the one across the parallel resistors.
 
uart said:
Yes there is. Can you draw the equivalent circuit? You have the internal EMF with the armature resistance in series, and then both the field resistance and load resistance in parallel to complete the circuit. The terminal voltage is the one across the parallel resistors.

Hi, thanks for the reply. I have tried to draw the equivalent circuit and calculate the values but to no success, is there any way you could show me how you would do it?

Thanks
 
Ive got this as the circuit, I'm not sure if its correct though.
 

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TimWillz said:
Ive got this as the circuit, I'm not sure if its correct though.

Yes that looks right. Use the rotational EMF constant to find Ea and also combine the field resistance and the load resistance into a single equivalent resistance. Now you can use the voltage divider formula to find the terminal voltage.
 
uart said:
Yes that looks right. Use the rotational EMF constant to find Ea and also combine the field resistance and the load resistance into a single equivalent resistance. Now you can use the voltage divider formula to find the terminal voltage.

Thanks! I've got Ea = 0.86*174.9 = 150.4v

Is it just (RA*RF*RL)/(RA+RF+RL) to find the total resistance?
 

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