- #1
Name15
- 30
- 1
Homework Statement
A permanent magnet DC motor has an armature resistance of 0.4 Ohms. When a voltage of 110 V is applied to the motor it reaches a steady-state speed of rotation of 126 rad/s and draws 39 A.
(a) Find the power loss in the armature
(b) the power input to the motor
I really don't know what I'm doing. I just used the equations I already know. What is the significance of steady state speed being reached? What do i do with the 126 rad/s?
Homework Equations
P=IV (power = current x voltage)
P=(I^2)(R) (power = current squared x resistance)
The Attempt at a Solution
(a) P = (39^2) x (0.4) = 608.4 W
(b) P = 39 x 110 = 4290 W