DC source rather than a clamper circuit?

[Sami1999]

Homework Statement

Why is it preferred to use a clipper circuit rather than a DC source to shift an AC source upwards on a voltage-time graph?

Relevant Equations

No relevant equations

Why is it preferred to use a clamper circuit rather than a DC source to shift an AC source upwards on a voltage-time graph?Both require a battery(DC source) so isn't it cheaper than having to use some extra elements like capacitors and diodes?

 

[NascentOxygen]

Can you provide an image of the proposed clamper circuit?

 

[Sami1999]

https://www.tutorialspoint.com/electronic_circuits/images/positive_clamper_circuit.jpgAnd I mistakenly wrote clipper instead of clamper

<Moderator's note: corrected.>

 

[NascentOxygen]

You can see that the circuit automatically adjusts its DC offset to follow the level of the signal.

 

[Sami1999]

I mean why not just place a battery in series with the source?
Shouldn't it have the same effect in the outcome.

 

[NascentOxygen]

I mean why not just place a battery in series with the source?
Shouldn't it have the same effect in the outcome.

You may not have access to the signal source. A battery would add a fixed DC offset, whereas the clamping arrangement adjusts for varying signal levels so the offset is just enough so the offset signal doesn't go negative.

 

[Tom.G]

Like @NascentOxygen said... and you would have to replace the battery on occasion.