DC Volts & Amps to Recharge 8.8 kWh Chevy Volt in 15 Min

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To recharge an 8.8 kWh Chevy Volt battery in 15 minutes, a high-voltage, low-current DC charging solution is essential to minimize power loss. The power required can be calculated using the formula P = IV, leading to the conclusion that a significant combination of volts and amps is necessary. Specifically, the calculation shows that 35.2 kW is needed, which translates to a voltage and current ratio that favors higher voltage. A Class III charger would ideally operate at a voltage that maximizes efficiency while maintaining a manageable current. This approach ensures rapid charging with minimal energy loss.
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Homework Statement



The fastest, most powerful Class III battery charger available is supposed to recharge 8.8 kWh into a Chevy Volt battery pack in 15 minutes. What is the most likely combination of DC volts and amps to do this and why?

Homework Equations



W=VxI (I = amps)
a 120 V unit can do 12 I in 6 hours

The Attempt at a Solution

 
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If I remember correctly, P = IV (not the work, but the rate of work -- power). That would mean that you would have 8.8 [kWh]/15 [min] = I*V (be sure to convert the units appropriately). For DC circuits, I would assume the most likely condition would be the one with an appropriately large V/I ratio (more voltage and less current would imply less power loss from resistance).
 
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