De Broglie wavelength calculations

Click For Summary
SUMMARY

The discussion centers on the calculation of the de Broglie wavelength for an alpha particle traveling at 2 x 106 m/s with a mass of 6.645 x 10-27 kg. The formula used is λ = h/p = h/mv(√(1 - (v²/c²))). The calculated wavelength is approximately 4.99 x 10-14 m. Participants confirm that the mass of an alpha particle is consistently 6.645 x 10-27 kg and discuss the negligible relativistic effects at low speeds, as well as the reasons wave-like properties are not observed in larger bodies due to their significantly smaller de Broglie wavelengths.

PREREQUISITES
  • Understanding of de Broglie wavelength calculations
  • Familiarity with relativistic mechanics
  • Knowledge of particle physics, specifically alpha particles
  • Basic proficiency in algebra and scientific notation
NEXT STEPS
  • Research the implications of relativistic effects on particle mass
  • Explore the concept of wave-particle duality in quantum mechanics
  • Learn about the de Broglie wavelength for various particles at different speeds
  • Investigate why wave-like properties are not observable in macroscopic objects
USEFUL FOR

Students and professionals in physics, particularly those studying quantum mechanics, particle physics, and anyone interested in the implications of wave-particle duality.

rugapark
Messages
22
Reaction score
0
I had a go at 2 Q's and wanted to make sure I'm doing this right.
so here's the first one, and maybe if i went wrong with it I was going to redo the 2nd Q on my own.

\lambda = h/p = h/mv (\sqrt{1-((v^2)/(c^2))})

so, an Alpha Particle traveling @ 2x106m/s (mass = 6.645x10-27 kg)

\lambda = [(6.626*10^-^3^4)/((6.645*10^-^2^7)*(2*10^6))] x {\sqrt{1-[(2*10^6)^2/(3*10^8)^2]}}

= (4.986x10-14) x (99.998x10-2)

= 4.99x10-14m

how does this look?
and also, am i right in assuming if the question does not state otherwise, that the mass of an alpha particle is always 6.645x10-27kg?

Cheers guys
Ruga
 
Physics news on Phys.org
That looks right. A particle's mass would increase as the particle's speed approaches the speed of light, so the wavelength decreases.

The rest mass of the alpha particle is always in its inertial frame 3727 MeV or 6.645 x 10-27 kg. In classical mechanics, particle mass usually refers to rest mass.
 
brilliant - just another quicky, some of the answer guides ignored the whole square root part of the equation.. is that because that part of the equation is always roughly equal to 1?
 
At low speeds, e.g. v = 0.01 c, then (v/c)2 = 0.0001, and the square root of 1-(0.01)2 = 0.99995, so the relativistic effect is very small.

Alpha particles coming from alpha decay or in fusion reactions have kinetic energies on the order of several MeV, so there speeds are not relativistic.
 
I ended up discussing something with friends when we were going through this question - why is it that we don't see wave like properties in larger bodies i.e. in macroscopic levels? is it because the larger the mass, the smaller the de Broglie wavelength, and so the wave like properties are just too small to be detected?
 
rugapark said:
I ended up discussing something with friends when we were going through this question - why is it that we don't see wave like properties in larger bodies i.e. in macroscopic levels? is it because the larger the mass, the smaller the de Broglie wavelength, and so the wave like properties are just too small to be detected?
Compare the 'size' of an alpha particle (or atomic nucleus) with the deBroglie wavelength (in the OP), then compare the wavelength of a 1 kg metal sphere (density = 8 g/cm3) with the deBroglie wavelength for different speeds, e.g. 10 m/s and 1000 m/s.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
4K