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De Broglie wavelength calculations

  1. Aug 9, 2008 #1
    I had a go at 2 Q's and wanted to make sure I'm doing this right.
    so here's the first one, and maybe if i went wrong with it I was going to redo the 2nd Q on my own.

    [tex]\lambda = h/p = h/mv (\sqrt{1-((v^2)/(c^2))})[/tex]

    so, an Alpha Particle travelling @ 2x106m/s (mass = 6.645x10-27 kg)

    [tex]\lambda = [(6.626*10^-^3^4)/((6.645*10^-^2^7)*(2*10^6))][/tex] x [tex]{\sqrt{1-[(2*10^6)^2/(3*10^8)^2]}}[/tex]

    = (4.986x10-14) x (99.998x10-2)

    = 4.99x10-14m

    how does this look?
    and also, am i right in assuming if the question does not state otherwise, that the mass of an alpha particle is always 6.645x10-27kg?

    Cheers guys
    Ruga
     
  2. jcsd
  3. Aug 9, 2008 #2

    Astronuc

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    Staff: Mentor

    That looks right. A particle's mass would increase as the particle's speed approaches the speed of light, so the wavelength decreases.

    The rest mass of the alpha particle is always in its inertial frame 3727 MeV or 6.645 x 10-27 kg. In classical mechanics, particle mass usually refers to rest mass.
     
  4. Aug 9, 2008 #3
    brilliant - just another quicky, some of the answer guides ignored the whole square root part of the equation.. is that because that part of the equation is always roughly equal to 1?
     
  5. Aug 9, 2008 #4

    Astronuc

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    At low speeds, e.g. v = 0.01 c, then (v/c)2 = 0.0001, and the square root of 1-(0.01)2 = 0.99995, so the relativistic effect is very small.

    Alpha particles coming from alpha decay or in fusion reactions have kinetic energies on the order of several MeV, so there speeds are not relativistic.
     
  6. Aug 10, 2008 #5
    I ended up discussing something with friends when we were going through this question - why is it that we don't see wave like properties in larger bodies i.e. in macroscopic levels? is it because the larger the mass, the smaller the de Broglie wavelength, and so the wave like properties are just too small to be detected?
     
  7. Aug 10, 2008 #6

    Astronuc

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    Staff: Mentor

    Compare the 'size' of an alpha particle (or atomic nucleus) with the deBroglie wavelength (in the OP), then compare the wavelength of a 1 kg metal sphere (density = 8 g/cm3) with the deBroglie wavelength for different speeds, e.g. 10 m/s and 1000 m/s.
     
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