I had a go at 2 Q's and wanted to make sure I'm doing this right.(adsbygoogle = window.adsbygoogle || []).push({});

so here's the first one, and maybe if i went wrong with it I was going to redo the 2nd Q on my own.

[tex]\lambda = h/p = h/mv (\sqrt{1-((v^2)/(c^2))})[/tex]

so, an Alpha Particle travelling @ 2x10^{6}m/s (mass = 6.645x10^{-27}kg)

[tex]\lambda = [(6.626*10^-^3^4)/((6.645*10^-^2^7)*(2*10^6))][/tex] x [tex]{\sqrt{1-[(2*10^6)^2/(3*10^8)^2]}}[/tex]

= (4.986x10^{-14}) x (99.998x10^{-2})

=4.99x10^{-14}m

how does this look?

and also, am i right in assuming if the question does not state otherwise, that the mass of an alpha particle is always 6.645x10^{-27}kg?

Cheers guys

Ruga

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# Homework Help: De Broglie wavelength calculations

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