Deducing the film thickness of this ques below:

  • Context: Graduate 
  • Thread starter Thread starter iCENA
  • Start date Start date
  • Tags Tags
    Film Thickness
Click For Summary
SUMMARY

The discussion focuses on deducing the film thickness of a thin soap film observed under sodium light, specifically at a wavelength of 5893 angstroms. The refractive index of the liquid is given as 1.333. The film appears dark due to destructive interference caused by a path difference of λ/2, resulting in a phase difference of π. The analysis concludes that the film thickness must be less than one wavelength for no light to be reflected, with the first observable thickness that produces darkness occurring at λ/2.

PREREQUISITES
  • Understanding of wave interference principles
  • Knowledge of refractive indices, specifically for liquids
  • Familiarity with the concept of phase change in light reflection
  • Basic knowledge of light wavelengths, particularly in angstroms
NEXT STEPS
  • Research the principles of light interference and its applications in optics
  • Study the effects of refractive index on light behavior in different media
  • Explore the concept of phase changes in wave reflections
  • Learn about the practical applications of thin films in technology and science
USEFUL FOR

Students and professionals in physics, optics researchers, and anyone interested in the properties of light and thin films.

iCENA
Messages
2
Reaction score
0
a thin soap film is seen in sodium light by normal reflection method it appears totally dark deduce the possible values of film thickness given (myu)-refra.indx of liquid-1.333 and lambda wave.lgth-5893 angstrom
 
Science news on Phys.org
This effect is caused by INTERFERENCE between light waves reflected from the front face of the soap film and light waves reflected from the back face, after passing into the film.
The waves will 'cancel out' if there is a path difference of λ/2 (a phase difference of ∏)
and the film will look dark because there is no light reflected.
There is a strange fact about waves. Light reflected from the air/film surface undergoes a phase change of ∏, this is like being given a λ/2 kick out of step.
Light reflected from the film/air surface does not experience a phase change.
This means that a very thin film (less than 1 wavelength) will produce no reflected light.
This is why you can be aware of the dark film when the film is about to burst.
The next thickness of film that will produce darkness is when the film is λ/2 thick (this is the λ in the film material) because the light travels 1 wavelength through the film (there and back)
and the resulting total path difference is λ/2 because of the λ/2 at the front surface.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
7
Views
6K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 20 ·
Replies
20
Views
6K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 5 ·
Replies
5
Views
9K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K