MHB Definite integral ∫(cos4x−cos4α)/(cosx−cosα)dx

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The definite integral I = ∫(cos 4x - cos 4α)/(cos x - cos α)dx is evaluated over the interval from 0 to π. The proposed solution indicates that the result is I = 4π cos 2α cos α. This conclusion is drawn from the observation that the constant is integrated over a length of π. The discussion emphasizes the correctness of this evaluation. The integral's solution highlights the relationship between the cosine functions and the variable α.
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Evaluate the definite integral:\[I = \int_{0}^{\pi}\frac{\cos 4x - \cos 4\alpha }{\cos x - \cos \alpha }dx\]- for some $\alpha \in \mathbb{R}.$
 
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[sp]It looks as though the answer should be $I = 4\pi\cos2\alpha\cos\alpha$ (because the constant is integrated over an interval of length $\pi$). (Cool)
[/sp]
 
Opalg said:
[sp]It looks as though the answer should be $I = 4\pi\cos2\alpha\cos\alpha$ (because the constant is integrated over an interval of length $\pi$). (Cool)
[/sp]

Yes, indeed. A factor $\pi$ is missing in the answer. I am so sorry for this typo!
 
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