Definite integral ∫(cos4x−cos4α)/(cosx−cosα)dx

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SUMMARY

The definite integral \( I = \int_{0}^{\pi}\frac{\cos 4x - \cos 4\alpha }{\cos x - \cos \alpha }dx \) evaluates to \( I = 4\pi\cos2\alpha\cos\alpha \). This conclusion is drawn from the observation that the constant term is integrated over an interval of length \( \pi \). The solution is confirmed through repeated analysis and verification within the discussion.

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lfdahl
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Evaluate the definite integral:\[I = \int_{0}^{\pi}\frac{\cos 4x - \cos 4\alpha }{\cos x - \cos \alpha }dx\]- for some $\alpha \in \mathbb{R}.$
 
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[sp]It looks as though the answer should be $I = 4\pi\cos2\alpha\cos\alpha$ (because the constant is integrated over an interval of length $\pi$). (Cool)
[/sp]
 
Opalg said:
[sp]It looks as though the answer should be $I = 4\pi\cos2\alpha\cos\alpha$ (because the constant is integrated over an interval of length $\pi$). (Cool)
[/sp]

Yes, indeed. A factor $\pi$ is missing in the answer. I am so sorry for this typo!
 

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