# Definite Integrals with inverse of function

## Homework Statement

Suppose f(x) is continuous and decreasing on the closed interval 5 <= x < 13, that f(5) = 9, f(13) = 5 and that the

integral of f(x) from 5 to 13 is 70.64758.

Then the integral of f^-1(x) from 5 to 9 is equal to what?

(Note: f^-1(x) is the inverse of f(x))

## The Attempt at a Solution

I really don't know how to solve this problem. I know that f^-1(f(x)) = x. Any ideas would be great. Thanks.

You want to find $$\int_{u=5}^9 f^{-1}(u)\,du$$
f is a positive monotone function on [a,b] where 0 < a < b and f has an inverse $$f^-1$$. Set $$\alpha = f(a), \beta = f(b)$$ and then use this formula:$$\int_{\alpha}^{\beta} f^-1(y) dy = b \beta - a \alpha - \int_a^b f(x) dx$$.
f is a positive monotone function on [a,b] where 0 < a < b and f has an inverse $$f^-1$$. Set $$\alpha = f(a), \beta = f(b)$$ and then use this formula:$$\int_{\alpha}^{\beta} f^-1(y) dy = b \beta - a \alpha - \int_a^b f(x) dx$$.