Definition of pound force

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The discussion revolves around the concept of pound force (lbf) and its application in physics, specifically in accelerating a mass of 32 pounds (lbm). Participants express frustration over the lack of practical demonstrations showing 1 lbf moving 32 lbm at a specific acceleration. The conversation highlights the complexities of unit conversions in the U.S. customary system, emphasizing that the formula F=ma is not straightforward due to the system's incoherence. One contributor points out that understanding the relationship between force, mass, and acceleration requires a grasp of unit conversion factors. The thread ultimately emphasizes the importance of guiding individuals toward understanding rather than simply providing answers.
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Homework Statement
prove by physical demonstaration1lbf accelerates 32lbm @ 1ft/s^2. Is there a pic of a classroom experiment proving this?
Relevant Equations
def 1lbf=32lbm*1ft/s^2
I can divide the #'s out, but so what. I want to see 1lbf move 32lbm.
 
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Roady said:
I want to see 1lbf move 32lbm.
Are you trying to convince yourself? Or a third party doubter? How direct does the proof need to be?
 
Roady said:
Does it matter? Can you answer the question?
The direct answer is that I know of no picture or video demonstrating a 32 pound weight being accelerated at 1 foot per second per second by a 1 pound force.

Given the available coefficients of friction, the best demonstration that I can think of would involve something like a pendulum bob on a long wire.
Roady said:
Do you know of a friggn experiment? I'm getting the most inane answers from respondants here; another:can you see your mistake?
Did I speak of your mistake or even imply that you'd made one? In this thread you have not made any mistakes. Up until now, you'd only asked a question.

Roady said:
Duh, if I could I wouldn't ask for help.
Here at physicsforums.com we help people help themselves. That means guiding people to an understanding. Not simply answering questions.
Roady said:
1lbf=m*g, what is that mass is another angle? 1lbf=32lbm*1f/s^2=1lbm*32/s^2, but this product is 32lbm*ft/s^2, so that has to account for something if it's not a pound force.
It sounds like you are trying to argue rather than to understand. And since you have another thread open on this same subject, I will stop responding here.

I will say that ##F=ma## only works in coherent systems of units. More generally the formula is ##F=kma## where ##k## is a unit conversion factor. The U.S. customary system is not coherent. In the U.S. system with pounds force, pounds mass and feet per second squared, ##F = \frac{1}{32}ma##
 
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Thread 'Chain falling out of a horizontal tube onto a table'
My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...

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