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[tex]U = -G\frac{Mm}{r}[/tex].

So am I right in thinking that, in this case,

[tex]H = \frac{1}{2}mv^{2} - G\frac{Mm}{r}[/tex]

and

[tex]L = \frac{1}{2}mv^{2} + G\frac{Mm}{r}[/tex] ?

That's to say, is the sign of the potential significant, rather than just the absolute value?