# Homework Help: Deflection of a Beam using Double Integration

1. Oct 23, 2007

### voodoonoodle

1. The problem statement, all variables and given/known data

Need to determine the maximum deflection of the beam, by using double integration, and EI is constant.

............>........<
_______(_______)_______
^..................................o
|<--a-->|<--a-->|<--a-->|

Tried to draw this the best I could. It is a simply supported beam, with a concentrated couples of equal value (C) but opposite direction, with a distance between of (a).

2. Relevant equations

I pretty sure that my boundary conditions are: v=0 @ x=0 and v=0 @ x=3a

and my max. deflection will occur at x=(3/2)a

3. The attempt at a solution

My problem is that I don't know how to get started, all the examples show only one concentrated moment. I'm assuming I have no reactions, because when I sum the moments around either side, the moments cancel out.

I have tried using that M=C(x-a) and that didn't come out correct. So basically I'm looking for help in trying to get the moment function.

I have also tried M=C where I get the following

slope as a function of x = Cx/EI + C1
deflection as a function of x = Cx^2/2EI + C1x + C2

boundary conditions:
v=0 @ x=0 so C2 = 0
v=0 @ x=3a so C1 = (-3(C)(a))/(2EI)

so then I come up with an answer of (-9(C)(a^2))/(8EI) for the max deflection using x=(3/2)a

Last edited: Oct 23, 2007
2. Oct 24, 2007

### PhanthomJay

Well, it's been way too long since I used the double integration method, but it does bring back some haunting memories. If you're looking at y" =M(x)/EI, my suggestion would be to calcualte M(x) using shear and moment diagrams. Looks to me like you've got no shear at all anywher along the beam, and just a constant moment of c in between the two applied couples, and no moment on either side of those couples to the support points.

3. Oct 24, 2007

### voodoonoodle

PhantomJay, that is correct. I'm just not sure how to come up with M(x). I have tried several things for it but still can't get the answer they give for Max Deflection. Which I know to be (5(C)(a^2))/(8EI).

4. Oct 24, 2007

### PhanthomJay

Well, M(x) =0 between 0 and a; M(x) = C between a and 2a; and M(x) = 0 between 2a and 3a. Now double integrate and use proper boundary conditions , which is probably what you're trying to do. I think the key is to deternine the boundary conditons. I've been relying on tables and charts, so my calculus is a bit rusty at this point.

5. Oct 18, 2009

### RTFVerterra

What a coincidence, I found this post: http://forums.mathalino.com/general-engineering-sciences/strength-of-materials/beam-deflection-by-double-integration-method" [Broken]. It is exactly the same problem as this one.

Last edited by a moderator: May 4, 2017