Deflection of Beams - Rearrange formula

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SUMMARY

The discussion focuses on calculating the force on a support for a simply supported beam experiencing deflection. The original deflection formula used is y = - (F x L^3)/(48 x E x I), where 'y' represents deflection, 'F' is the force, 'L' is the length of the beam, 'E' is the modulus of elasticity, and 'I' is the moment of inertia. The user calculated a deflection of 9.72mm and adjusted it to 3.72mm to find the force, ultimately arriving at a value of 2.212 MPa, which was questioned against an original load of 80 kN. The user confirmed the solution process and resolved their confusion regarding the support configuration.

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  • Understanding of beam deflection principles
  • Familiarity with the formula for deflection of beams
  • Knowledge of modulus of elasticity (E) and moment of inertia (I)
  • Basic algebra for rearranging equations
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Deflection of Beams - Rearrange formula [URGENT]

Homework Statement



Deflection for a simply supported beam... I calculated the deflection of it to be 9.72mm downwards, but there is a support 6mm from the original position and need to calculate the force on the support...

The original formula for deflection is:

y = - (F x L^3)/(48 x E x I)

where 'x' is just the multiplication symbol.


Homework Equations



y = - (F x L^3)/(48 x E x I)

The Attempt at a Solution



To find the force on the support, I went 9.72-6 = 3.72mm

I substituted 3.72 into the equation above as 'y', now, how do i rearrange the formula to find F?

My attempt:

F = (48 x E x I)/(Y x L^3)

I get 2.212 MPa, this surely can't be right as the original load on top is 80KN. Did I rearrange correctly?


 
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Is this a beam on 3 supports?
 


Simply supported, no, not 3 supports, doesn't matter I've figured it out now. Thanks.
 

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