Delay and Sum Beamforming Equation Derivation

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SUMMARY

The discussion focuses on the derivation of the Delay and Sum Beamforming equations, specifically simplifying equation 1, e^-ix((1-e^y)/(1-e^z)), to equations 2 and 3. The key relationships established include M = 2*M_(1/2) + 1, which is crucial for transitioning from equation 1 to equation 2, sin(M*Beta/2)/(sin(Beta/2). The use of Euler's formula, e^jx = cos(x) + j*sin(x), is emphasized for transforming the expressions involving sine and cosine. The participants seek clarity on the notation M_(1/2) and its relationship to M, which is essential for the simplification process.

PREREQUISITES
  • Understanding of beamforming concepts in signal processing.
  • Familiarity with Euler's formula and its applications in complex analysis.
  • Knowledge of trigonometric identities, specifically the sinc function.
  • Basic algebraic manipulation skills for simplifying equations.
NEXT STEPS
  • Study the derivation of the sinc function and its properties in signal processing.
  • Learn about the applications of beamforming in wireless communications.
  • Explore advanced topics in complex analysis, focusing on Euler's formula.
  • Investigate the implications of M and M_(1/2) in beamforming equations.
USEFUL FOR

Signal processing engineers, researchers in wireless communications, and students studying advanced mathematics related to beamforming techniques.

mastrepolo
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Homework Statement


I have to simplify this beam form (equation 1) which simplifies to equation 2 and then finally to equation 3.

Homework Equations


equation 1: e^-ix((1-e^y)/(1-e^z)) where x = Beta*M_(1/2), y = beta*M, z= Beta

equation 2: sin(M*Beta/2)/(sin(Beta/2))

equation 3: M((sinc(M*Beta/2pi))/(sinc(Beta/2pi))) where sinc(x) = sin(pi*x)/pi*x

Eulors: e^jx = cos(x) +j*sin(x)

The Attempt at a Solution



I have tries to use eulors equation to change it to sine sand cosine but I can't seem to get the proper cancellations i am looking for.
 
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mastrepolo said:
equation 1: e^-ix((1-e^y)/(1-e^z)) where x = Beta*M_(1/2), y = beta*M, z= Beta
What is M_(1/2)?
Do you mean ##e^{-i\frac{\beta}2(M-1)}\frac{1-e^{i\beta M}}{1-e^{i\beta}}##?
 
Sorry about the late response. It is M1/2 as a subscript, I attached a picture. I am going to the math department for some guidance since I can't seem to figure this one out. Any help would be appreciated,
 

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mastrepolo said:
It is M1/2 as a subscript,
So what is the relationship between that and M? To get your eqn 2 I need it to equal (M-1)/2.
 
haruspex said:
So what is the relationship between that and M? To get your eqn 2 I need it to equal (M-1)/2.

To get it in this form we had to assume M = 2*M1/2+1. so . There were some other step to get it into the equation form but this is where it originated from.
 

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mastrepolo said:
To get it in this form
Are you saying to get eqn 1 you already assumed that?
I assume you know how to write sin x in terms of eix.
Can you see how to write 1-e-ix as some function f(x) multiplied by a sine function (not necessarily sin(x), exactly).
 

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