Deliberate riseball (dimple) from a baseball pitch

  • Thread starter Thread starter chuckspnz
  • Start date Start date
  • Tags Tags
    Baseball Pitch
AI Thread Summary
It is theoretically impossible for a baseball to rise to a near vertical position during a pitch due to the laws of physics, but the perception of a "rising fastball" is created by the Magnus effect, which results from backspin. This effect causes the ball to fall less rapidly than expected, leading to an optical illusion for the batter. While a human cannot throw a baseball fast enough to achieve actual rise, certain lighter balls, like a wiffle ball, may exhibit more pronounced rising effects. Techniques such as gripping the ball with four seams and throwing with strong backspin can create a flatter trajectory, enhancing the illusion of rise. Overall, the discussion highlights the interplay between physics and perception in baseball pitching.
chuckspnz
Messages
2
Reaction score
1
Is it possible to pitch a ball as a fastball (e.g. like in baseball) and have the ball rise to a near vertical and then fall back down to the ground. The ball would obviously have an altered design/features to cause it to lift/rise, but just wondering whether that sounds like something that could work. Apologies if this question makes no sense and completely defies the laws of physics, I am definitely not an expert rather a curious mind. I was recently at a beach throwing seashells into the water, and I noticed a few shells that I had tossed ended up flying to amazing heights when thrown at a horizontal. Wanted to know if the same could be done with something spherical.

Thanks
 
Physics news on Phys.org
https://en.wikipedia.org/wiki/Fastball
Fastballs are usually thrown with backspin, so that the Magnus effect creates an upward force on the ball. This causes it to fall less rapidly than expected, and sometimes causes an optical illusion often called a rising fastball. Although it is impossible for a human to throw a baseball fast enough and with enough backspin for the ball to actually rise, to the batter the pitch seems to rise due to the unexpected lack of natural drop on the pitch.
 
  • Like
Likes chuckspnz
Maybe not a baseball, but a whiffle ball, maybe? See 4:07 of this video.
 
  • Like
Likes chuckspnz
Makes sense, thanks everyone
 
  • Like
Likes berkeman
Back in high school, we had a new baseball coach come to our school when I was a freshman. He taught us how to pull the ball out of our glove holding 4 seams (takes practice, but becomes instinctive after a while), and how to throw the ball with strong backspin as infielders and outfielders. From the outfield, that makes the ball appear to rise for a bit, and then fall more slowly on the way to the target.

I understand now that it is a bit of an optical illusion that it rises at first, but for sure it makes the ball's path much flatter for throws across the infield or from the outfield to the infield.
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...

Similar threads

Back
Top