Density of star from hydrostatic equilibrium and pressure

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Homework Help Overview

The discussion revolves around the relationship between pressure and density in a star, specifically using the equation of state p = (1/2)kρ². Participants are exploring the implications of hydrostatic equilibrium and Poisson's equation in a stellar context.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to derive a relationship between density and gravitational potential, questioning the assumptions behind the equations used. There is discussion about the application of Poisson's equation and the correct form of the Laplacian in spherical coordinates.

Discussion Status

Some participants have made progress in deriving the necessary equations, while others are seeking clarification on specific steps and the application of relevant equations. There is an acknowledgment of differing interpretations regarding the boundary conditions and the form of the equations involved.

Contextual Notes

Participants note that the equation p + ρΦ = constant is typically valid for incompressible fluids, raising questions about its applicability in this context. There are also discussions about the implications of boundary conditions on the solutions being sought.

Dazed&Confused
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Homework Statement


Assume that the pressure p in a star with spherical symmetry is related to the density \rho by the (distinctly unrealistic) equation of state p= \tfrac12 k\rho^2, where k is a constant. Use the fluid equilibrium equation obtained in Problem 23 to find a relation between \rho and \Phi. Hence show that Poisson's equation yields
<br /> \frac{d^2[r\rho(r)]}{dr^2} = -\frac{4 \pi G}{k}r \rho(r)<br />
Solve this equation with the boundary conditions that \rho is finite at r=0 and vanishes at the surface of the star. Hence show that the radius a of the star is determinde solely by k and is independent of its mass M. Show also that M =(4/ \pi )a^4 \rho(0).

Homework Equations


\nabla p = \rho \textbf{g} and p + \rho \Phi = \textrm{constant}. And \nabla^2 \Phi = 4\pi G \rho.

The Attempt at a Solution


Assuming the differential equation, I am able to do the rest of the question. The relation they are looking for is \Phi = -k\rho and this can be easily shown by
\nabla p = k\rho&#039;(r) \rho(r) \hat{\textrm{r}} = \rho \textrm{g} and so
-\nabla \Phi = \textrm{g} = k\rho&#039;(r) \hat{\textrm{r}}

from which you can get \Phi. However by the second relevant equation this must also mean that -\tfrac12 k \rho^2 = \textrm{constant}, or I'm missing something. I've also not been able to obtain the differential equation.
 
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Not that it matters too much but it should be M = (4/\pi)a^3\rho(0). Any ideas anyone?

Edit 2: the equation p + \rho \Phi = \textrm{constant} is only for an incompressible fluid, so there is no contradiction.
 
Last edited:
Dazed&Confused said:
-\nabla \Phi = \textrm{g} = k\rho&#039;(r) \hat{\textrm{r}}

Note that this is just ##\nabla \Phi = -k \nabla \rho##.

To relate this to Poisson's equation, take the divergence of both sides.
 
Hi thanks for responding. I did realize this and found the relation they wanted. I took the Laplacian of this which did not work, so unsurprisingly taking the divergence of what you have said does not work either.
 
Yes I did use them. Could you try to see if you get the correct differential equation?
 
Yes, I am getting the correct differential equation. Can you show your work?
 
Certainly. I used Poisson's equation on the relation, so <br /> \nabla^2 \Phi = 4 \pi G \rho = -k \nabla^2 \rho = -k\frac{1}{r^2} \frac{d}{dr} \left ( r^2 \frac{d\rho}{dr} \right )

from which I can't get the correct equation.
 
OK, that looks good so far. Try re-expressing the right hand side.
 
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Thanks I was able to get it.
 

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