- #1
Dazed&Confused
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Homework Statement
Assume that the pressure [itex]p[/itex] in a star with spherical symmetry is related to the density [itex]\rho[/itex] by the (distinctly unrealistic) equation of state [itex]p= \tfrac12 k\rho^2[/itex], where [itex]k[/itex] is a constant. Use the fluid equilibrium equation obtained in Problem 23 to find a relation between [itex]\rho[/itex] and [itex]\Phi[/itex]. Hence show that Poisson's equation yields
[tex]
\frac{d^2[r\rho(r)]}{dr^2} = -\frac{4 \pi G}{k}r \rho(r)
[/tex]
Solve this equation with the boundary conditions that [itex]\rho[/itex] is finite at [itex]r=0[/itex] and vanishes at the surface of the star. Hence show that the radius [itex]a[/itex] of the star is determinde solely by [itex]k[/itex] and is independent of its mass [itex]M[/itex]. Show also that [itex]M =(4/ \pi )a^4 \rho(0)[/itex].
Homework Equations
[itex]\nabla p = \rho \textbf{g}[/itex] and [itex]p + \rho \Phi = \textrm{constant}[/itex]. And [itex] \nabla^2 \Phi = 4\pi G \rho [/itex].
The Attempt at a Solution
Assuming the differential equation, I am able to do the rest of the question. The relation they are looking for is [itex] \Phi = -k\rho[/itex] and this can be easily shown by
[tex] \nabla p = k\rho'(r) \rho(r) \hat{\textrm{r}} = \rho \textrm{g} [/tex] and so
[tex] -\nabla \Phi = \textrm{g} = k\rho'(r) \hat{\textrm{r}} [/tex]
from which you can get [itex] \Phi[/itex]. However by the second relevant equation this must also mean that [itex]-\tfrac12 k \rho^2 = \textrm{constant}[/itex], or I'm missing something. I've also not been able to obtain the differential equation.