Depletion region in n-type ohmic contact

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SUMMARY

The discussion focuses on the formation of an ohmic contact between a metal and an n-type semiconductor, highlighting the upward bending of the energy bands in the n-type material. This bending occurs due to the accumulation of negative charge within the semiconductor, which creates an electric field that halts further electron flow from the metal. The presence of a non-zero charge density leads to the depletion of electrons from the metal and their accumulation in the semiconductor, resulting in a net negative charge.

PREREQUISITES
  • Understanding of semiconductor physics
  • Knowledge of n-type semiconductor properties
  • Familiarity with energy band theory
  • Basic principles of electric fields and charge density
NEXT STEPS
  • Research the mechanisms of charge carrier movement in semiconductors
  • Explore the concept of energy band bending in p-n junctions
  • Learn about ohmic versus Schottky contacts in semiconductor devices
  • Investigate the effects of temperature on semiconductor behavior
USEFUL FOR

Electrical engineers, semiconductor physicists, and students studying solid-state electronics will benefit from this discussion, particularly those interested in the behavior of n-type semiconductors and ohmic contacts.

PF123
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Hello every one,

Here in below figure we can see an ohmic contact formation between a metal and n-type semiconductor .
Untitled_zps36e0b9cf.jpg


Here how the N-type semiconductor bands are banded upward ?
and what type of depletion charge exists there ?
 
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electrons will flow into the semiconductor from the metal until enough negative charge has accumulated in the semiconductor to give an electric field strong enough to stop the flow of charge. The electric field comes from the semiconductor having a net negative charge (where before it was neutral). The bands are bent whenever you have a non-zero charge density. Electrons are depleted from the metal and accumulated in the semiconductor.
 

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